Given:
Outer Diameter, OD = 90 mm
thickness, t = 0.1656 mm
Poisson's ratio,
= 0.334
Strength = 320 MPa
Pressure, P =3.5 MPa
Formula Used:
1).
=
2). factor of safety, m = 
Explanation:
Now, for Inner Diameter of cylinder, ID = OD - 2t
ID = 90 - 2(1.65) = 86.7 mm
Outer radius,
= 45mm
Inner radius,
= 43.35 mm
Now by using the given formula (1)
=
=
=93.74 MPa
Now, Using formula (2)
factor of safety, m = \frac{320}{93.74} = 3.414
Answer:
70.66 cm^3
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
Explanation:
Viral equation : Z = 1 + Bp + Cp^2 + Dp^3 + -----
Viral equation can also be rewritten as :
Z = 1 + B ( P/RT )
B ( function of time )
Temperature = 310 K
P1 = 8 bar
P2 = 75 bar
<u>Determine the specific volume in cm^3 </u>
V = 70.66 cm^3
<u>b) comparing the specific volumes to the experimental values </u>
70.58 and 3.90
The specific volume for P = 70.66 is within 1% of the experimental value while the viral equation will be inaccurate when the second viral coefficient is used )
attached below is the detailed solution
Explanation:
There are two ways to find out the equivalent impulse response of the system.
1. Convolution in time domain
2. Simple multiplication in Laplace domain
2nd method is efficient, easy and is less time consuming.
Step 1: Take the Laplace transform of the given three impulse response functions to convert time domain signals into s-domain
Step 2: Once we get signals in s-domain, multiply them algebraically to get the equivalent s-domain response.
Step 3: Take inverse Laplace transform of the equivalent impulse response to convert from s-domain into time domain.
Solution using Matlab:
Step 1: Take Laplace Transform
Ys1 = 1/(s + 1)
Ys2 = 1/s - exp(-s/2)/s
Ys3 = exp(-3*s)
Step 2: Multiplication in s-domain
Y = (exp(-(7*s)/2)*(exp(s/2) - 1))/(s*(s + 1))
Step 3: Inverse Laplace Transform (Final Solution in Time Domain)
h = heaviside(t - 7/2)*(exp(7/2 - t) - 1) - heaviside(t - 3)*(exp(3 - t) - 1)
Answer:
58.44 g/mol The Molarity of this concentration is 0.154 molar
Explanation:
the molar mass of NaCl is 58.44 g/mol,
0.9 % is the same thing as 0.9g of NaCl , so this means that 100 ml's of physiological saline contains 0.9 g of NaCl. One liter of physiological saline must contain 9 g of NaCl. We can determine the molarity of a physiological saline solution by dividing 9 g by 58 g... since we have 9 g of NaCl in a liter of physiological saline, but we have 58 grams of NaCl in a mole of NaCl. When we divide 9 g by 58 g, we find that physiological saline contains 0.154 moles of NaCl per liter. That means that physiological saline (0.9% NaCl) has a molarity of 0.154 molar. We can either express this as 0.154 M or 154 millimolar (154 mM).
Answer:
Absolute viscosity is the evaluation of the resistance (INTERNAL) of the fluid flow
Kinematic viscosity relates to the dynamic viscosity and density proportion.
SUS stands for Sabolt Universal Seconds. it is units which described the variation of oil viscosity
Explanation:
Absolute viscosity is the evaluation of the resistance (INTERNAL) of the fluid flow, whereas Kinematic viscosity relates to the dynamic viscosity and density proportion. fluid with distinct kinematic viscosities may have similar dynamic viscosities and vice versa.Dynamic viscosity provides you details of power required to make the fluid flow at some rate, however kinematic viscosity shows how quick the fluid moves when applying a certain force.
SUS stands for Sabolt Universal Seconds. it is units which described the variation of oil viscosity when change with change in temperature. it is measured by using viscosimeter.