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3 years ago

What is the speed of a vehicle with a distance of 88 miles and a time of 4 hours????

Physics

2 answers:

Tanya [424]3 years ago

7 0

The answer you are looking for is 22 mph.

Solution:

s=speed

d=distance

t=time

Setting up the formula for the speed of an object with distance and time:

s=d/t

Substituting the given values,

s=88 miles/4 hours

So, therefore, the final answer is 22 mph.

I hope this helped answer your question for you. Good day to you.

sleet_krkn [62]3 years ago

3 0

Answer:

352 miles answer

Explanation:

guessing that he kept going in a constant speed of 88 miles first you multiyply 88x4 which gives you 352 hoped it helped

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3 years ago

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Answer:

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Explanation:

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A circular test track for cars has a circumference of 3.5 kmkm . A car travels around the track from the southernmost point to t

elixir [45]

Answer:

(A) Distance will be equal to 1.75 km

(B) Displacement will be equal to 1.114 km

Explanation:

We have given circumference of the circular track = 3.5 km

Circumference is given by $2\pi r=3.5$

r = 0.557 km

(a) It is given that car travels from southernmost point to the northernmost point.

For this car have to travel the distance equal to semi perimeter of the circular track

So distance will be equal to $=\frac{3.5}{2}=1.75km$

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8 0

3 years ago

A man whose mass is 69 kg and a woman whose mass is 52 kg sit at opposite ends of a canoe 5 m long, whose mass is 20 kg. Suppose

dusya [7]

Answer:

the canoe moved 1.2234 m in the water

Explanation:

Given that;

A man whose mass = 69 kg

A woman whose mass = 52 kg

at opposite ends of a canoe 5 m long, whose mass is 20 kg

now let;

x1 = position of the man

x2 = position of canoe

x3 = position of the woman

Now,

Centre of mass = [m1x1 + m2x2 + m3x3] / m1 + m2 + m3

= ( 69×0 ) + ( 52×5) + ( 20× 5/2) / 69 + 52 + 20

= (0 + 260 + 50 ) / ( 141 )

= 310 / 141

= 2.19858 m

Centre of mass is 2.19858 m

Now, New center of mass will be;

52 × 2.5 / ( 69 + 52 + 20 )

= 130 / 141

= 0.9219858 m { away from the man }

To get how far, the canoe moved;

⇒ 2.5 + 0.9219858 - 2.19858

= 1.2234 m

Therefore, the canoe moved 1.2234 m in the water

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