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3 years ago

What is the speed of a vehicle with a distance of 88 miles and a time of 4 hours????

Physics

2 answers:

Tanya [424]3 years ago

7 0

The answer you are looking for is 22 mph.

Solution:

s=speed

d=distance

t=time

Setting up the formula for the speed of an object with distance and time:

s=d/t

Substituting the given values,

s=88 miles/4 hours

So, therefore, the final answer is 22 mph.

I hope this helped answer your question for you. Good day to you.

sleet_krkn [62]3 years ago

3 0

Answer:

352 miles answer

Explanation:

guessing that he kept going in a constant speed of 88 miles first you multiyply 88x4 which gives you 352 hoped it helped

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А)

loris [4]

Image of the plate is missing, so i have attached it.

Answer:

A) t = 7.854 mm

B) σ = 26.67 MPa

Explanation:

A) From shearing of rivet, formula for pressure is;

P = τ•A_rivets

Where;

τ is allowable stress

A_rivets is Area of rivet

We are given:

τ = 60 MPa

Diameter; d = 20 mm

A_rivets = πd²/4 = π × 20²/4 = 100π

Thus;

P = 60 × 100π

P = 6000π N

From bearing of plate material, we can calculate pressure as;

P = σ_b•A_b

We are given;

σ_b = 120 MPa

A_b is area of plate = 20t

Where t is the thickness

Thus;

6000π = 120 × 20t

t = 6000π/(120 × 20)

t = 7.854 mm

B) Largest average tensile stress is given by the formula;

σ = P/A

Where A = 110t - 20t

A = 90t

A = 90 × 7.854

Thus;

σ = 6000π/(90 × 7.854)

σ = 26.67 MPa

8 0

3 years ago

Which phrases describe the atmosphere? Check all that apply.

vladimir2022 [97]

Answer:

There is no options for this answer

Explanation:

7 0

3 years ago

Why is the position vs. time graph for an object in free fall a curve?

Ymorist [56]

Under free fall, the object is falling with a velocity that is increasing uniformly. Since the gradient of position-time graph reflects the velocity, the gradient is increasing, i.e. curve.

7 0

3 years ago

Long, long ago, on a planet far, far away, a physics experiment was carried out. First, a 0.210-kg ball with zero net charge was

tigry1 [53]

Answer:

$\Delta V=316167V$

Explanation:

The difference of electric potential between two points is given by the formula $\Delta V=Ed$ , where d is the distance between them and E the electric field in that region, assuming it's constant.

The electric field formula is $E=\frac{F}{q}$ , where F is the force experimented by a charge q placed in it.

Putting this together we have $\Delta V=\frac{Fd}{q}$ , so we need to obtain the electric force the charged ball is experimenting.

On the second drop, the ball takes more time to reach the ground, this means that the electric force is opposite to its weight W, giving a net force $N=W-F$ . On the first drop only W acts, while on the second drop is N that acts.

Using the equation for accelerated motion (departing from rest) $d=\frac{at^2}{2}$ , so we can get the accelerations for each drop (1 and 2) and relate them to the forces by writting:

$a_1=\frac{2d}{t_1^2}$

$a_2=\frac{2d}{t_2^2}$

These relate with the forces by Newton's 2nd Law:

$W=ma_1$

$N=ma_2$

Putting all together:

$N=W-F=ma_1-F=ma_2$

Which means:

$F=ma_1-ma_2=m(a_1-a_2)=m(\frac{2d}{t_1^2}-\frac{2d}{t_2^2})=2md(\frac{1}{t_1^2}-\frac{1}{t_2^2})$

And finally we substitute:

$\Delta V=\frac{Fd}{q}=\frac{2md^2}{q}(\frac{1}{t_1^2}-\frac{1}{t_2^2})$

Which for our values means:

$\Delta V=\frac{2(0.21Kg)(1m)^2}{7.7\times10^{-6}C}(\frac{1}{(0.35s)^2}-\frac{1}{(0.65s)^2})=316167V$

7 0

3 years ago

FIRST ONE TO ANSWER GETS A BRAINLY!!! PLZ HELP ME!!!

Mandarinka [93]

Answer:

The number of coils of the wire and the strength of the power source.

Explanation:

It is a direct relationship meaning when one increases so does the other. A stronger power source will induce a stronger magnetic force. The more coils the stronger the magnet.

7 0

4 years ago