Answer:
La respuesta está en la explicación
Explanation:
Los átomos que no poseen ___<em>CARGA</em>____ son conocidos como ____<em>ÁTOMOS</em>____ ____<em>NEUTROS</em>_____. Los átomos que poseen carga se denominan ___<em>IONES</em>____, aquellos con carga positiva de llaman ____<em>PROTONES</em>____ y son aquellos que __<em>PIERDEN</em>__ electrones. Los ______<em>ANIONES</em>____ son aquellos con carga negativa y son los que _____<em>GANAN</em>___ electrones. Para todos los casos el valor de _<em>MASA</em>__ y _<em>NÚMERO ATÓMICO</em>_ permanecen iguales y son los que sacamos de la tabla periódica.
First, let's state the chemical reaction:
We can find the number of moles of Cl2 required to produce 0.0923 moles of AlCl3, doing a rule of three: 3 moles of Cl2 reacted produces 2 moles of AlCl3:
The calculation would be:
And the final step is to convert this number of moles to grams. Remember that the molar mass can be calculated using the periodic table, so the molar mass of Cl2 is 70.8 g/mol, and the conversion is:
The answer is that we need 9.770 grams of Cl2 to produce 0.0923 moles of AlCl3.
it is nutrients that's it
Answer:
reaction B is the best one I would choose
1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon.
Hence, in this case the mass of carbon in 8.46 g of CO2:
(12/44) × 8.46 = 2.3073 g
1 mole of water contains 18 g, out of which 2 g is hydrogen;
Therefore, 2.6 g of water contains;
(2/18) × 2.6 = 0.2889 g of hydrogen.
Therefore, with the amount of carbon and hydrogen from the hydrocarbon we can calculate the empirical formula.
We first calculate the number of moles of each,
Carbon = 2.3073/12 = 0.1923 moles
Hydrogen = 0.2889/1 = 0.2889 moles
Then, we calculate the ratio of Carbon to hydrogen by dividing with the smallest number value;
Carbon : Hydrogen
0.1923/0.1923 : 0.2889/0.1923
1 : 1.5
(1 : 1.5) 2
= 2 : 3
Hence, the empirical formula of the hydrocarbon is C2H3
