Answer:
H₂O is the limiting reactant
Theoretical yield of 240 g Al₂O₃ and 14 g H₂
Explanation:
Find how many moles of one reactant is needed to completely react with the other.
6.5 mol Al × (3 mol H₂O / 2 mol Al) = 9.75 mol H₂O
We need 9.75 mol of H₂O to completely react with 6.5 mol of Al. But we only have 7.2 mol of H₂O. Therefore, H₂O is the limiting reactant.
Now find the theoretical yield:
7.2 mol H₂O × (1 mol Al₂O₃ / 3 mol H₂O) × (102 g Al₂O₃ / mol Al₂O₃) ≈ 240 g Al₂O₃
7.2 mol H₂O × (3 mol H₂ / 3 mol H₂O) × (2 g H₂ / mol H₂) ≈ 14 g H₂
Since the data was given to two significant figures, we must round our answer to two significant figures as well.
Total in pot=28 L
400 mL in each bowl
16 bowls filled
1000mL=1L
16 bowls(400mL/1 bowl)=6400mL
6400mL(1L/1000mL)=6.4L
28L-6.4L=21.6 L
Capillary action is the ability of a liquid to flow in narrow spaces without the assistance of, or even in opposition to, external forces like gravity.
Answer:
1 mole of iron =6.023×10^23 particles
1 particles of iron=1/6.023×10^23 mole
7.46×10^25 particles =1/6.023×10^23×7.46×10^25
=1.238×10^48 mole is a required answer.
Answer:
P2 = 1250mmHg
Explanation:
V1 = 5.0L
P1 = 750mmHg
V2 = 3.0L
P2 = ?
According to Boyle's law, the volume of a fixed mass of gas is inversely proportional to its pressure provided that temperature remains constant.
P = k/V k = P*V
P1*V1 = P2*V2 = P3*V3 =........=Pn*Vn
P1 *V1 = P2 * V2
Solve for P2
P2 = (P1 * V1) / V2
P2 = (750 * 5.0) / 3.0
P2 = 3750 / 3
P2 = 1250mmHg
The final pressure of the gas is 1250mmHg
