Flame test is a qualitative test which is used to identify the metal and metalloid ion in the sample.
<h3>What is Flame Test ?</h3>
A Flame test is used to identify the metal and metalloid ion in the sample. Flame test is a qualitative test. Not every metal ion emit color when it is heated in the gas burner.
<h3>What is the Purpose of Flame test ?</h3>
The purpose of flame test is used to find the identities of ions in two solutions of unknown composition by comparing the colors they produce.
<h3>What are the material used ?</h3>
- Bunsen Burner
- Matches
- Gloves
- Weighing dishes
- Beakers
Thus from the above conclusion we can say that Flame test is a qualitative test which is used to identify the metal and metalloid ion in the sample.
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The empirical formula of the following compounds 0.903 g of phosphorus combined with 6.99 g of bromine.
<h3>What is empirical formula?</h3>
The simplest whole number ratio of atoms in a compound is the empirical formula of a chemical compound in chemistry. Sulfur monoxide's empirical formula, SO, and disulfur dioxide's empirical formula, S2O2, are two straightforward examples of this idea. As a result, both the sulfur and oxygen compounds sulfur monoxide and disulfur dioxide have the same empirical formula.
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How to find the empirical formula?</h3>
Convert the given masses of phosphorus and bromine into moles by multiplying the reciprocal of their molar masses. The molar masses of phosphorus and bromine are 30.97 and 79.90 g/mol, respectively.
Moles phosphorus = 0.903 g phosphorus
= 0.0293 mol
Moles bromine 6.99 g bromine
=0.0875 mol
The preliminary formula for compound is P0.0293Bro.0875. Divide all the subscripts by the subscript with the smallest value which is 0.0293. The empirical formula is P1.00Br2.99 ≈ P₁Br3 or PBr3
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Answer:
The answer is North
Explanation:
The direction of the field is taken to be the direction of the force it would exert on a positive test charge.