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In-s [12.5K]
3 years ago
6

H2 and I2 react in an exothermic reaction according to the following equation:

Chemistry
1 answer:
Alborosie3 years ago
8 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

For the given chemical reaction:

H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

Catalyst is a chemical substance which alters the rate of the reaction and does not participate in the reaction. It does not effect the equilibrium position.

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle. This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

  • <u>Change in volume:</u>

Any change in volume during equilibrium is studied on the basis of change in moles of gaseous reactants and gaseous products.

When volume is decreased, the equilibrium will shift in the direction which produces fewer moles of gas and when volume is increased, the equilibrium will shift in the direction which produces more moles of gas.

  • <u>Change in pressure:</u>

Any change in pressure during equilibrium is studied on the basis of change in moles of gaseous reactants and gaseous products.

When pressure is decreased, the equilibrium will shift in the direction, which produces fewer moles of gas and when pressure is increased, the equilibrium will shift in the direction which produces more moles of gas.

Number of moles of gases on reactant side = [1 + 1] = 2

Number of moles of gases on product side = 2

Change in number of moles = 2 -2 = 0

As, number of moles on both the side of the reaction is same. This means there will be no effect on change in volume and change in pressure.

  • <u>Change in temperature:</u>

For an exothermic reaction, heat is released during a chemical reaction and is written on the product side.

A\rightleftharpoons B+\text{ heat}

As, heat is released during a chemical reaction. This means that temperature is decreased on the reactant side. If the temperature in the equilibrium is decreased, the equilibrium will shift in the direction where, temperature is getting increased. Thus, the reaction will shift in right direction that is towards the product.

So, lowering the temperature of the system will shift the position of equilibrium.

Hence, the correct answer is Option D.

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Use the periodic table and example bond table to answer the question.
lyudmila [28]

In keeping with the general trends, K-Br will have the smallest bond energy. The bond energy refers to the energy that keeps the atoms in a bond together.

<h3>What is bond energy?</h3>

Bond energy is the energy that is required to hold atoms together in a bond. This energy must also be supplied when the atoms are to be separated.

We have the bond energies of each of the bons in the question, we have to note that the the smallest value of bond energy is Na-Br hence in keeping with the general trends, K-Br will have the smallest bond energy.

Learn more about bond energies: brainly.com/question/14842720?

7 0
1 year ago
There are 7 named classes of hazardous materials.<br> O True<br> O False
Anika [276]
False

there is actually 9
7 0
2 years ago
a graduated cylinder has 35.0 mL of water in it before an object is dropped inside. the new volume is 38.5 mL. What is the volum
tino4ka555 [31]
Displaced volume:

final volume - initial volume

1 mL = 1 cm³

38.5 mL - 35.0 mL = 3.5 cm³

hope this helps!
4 0
3 years ago
What is the volume of 0.640 grams of Oz gas at Standard Temperature and Pressure (STP)?
Ilia_Sergeevich [38]

Answer: The volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

Explanation:

Given: Mass of O_{2} gas = 0.640 g

Pressure = 1.0 atm

Temperature = 273 K

As number of moles is the mass of substance divided by its molar mass.

So, moles of O_{2} (molar mass = 32.0 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{0.640 g}{32.0 g/mol}\\= 0.02 mol

Now, ideal gas equation is used to calculate the volume as follows.

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature

Substitute the values into above formula as follows.

PV = nRT\\1.0 atm \times V = 0.02 mol \times 0.0821 L atm/mol K \times 273 K\\V = 0.449 L

Thus, we can conclude that the volume of 0.640 grams of O_{2} gas at Standard Temperature and Pressure (STP) is 0.449 L.

6 0
3 years ago
What are the 3 best solutions to reducing or stopping the effects of climate change?
postnew [5]

Answer:

1. Stop Cutting down Trees

2. Control Population

3. Less use of Fossil Fuels

Explanation:

your welcome :)

4 0
3 years ago
Read 2 more answers
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