All categories

3 years ago

H2 and I2 react in an exothermic reaction according to the following equation:

Chemistry

1 answer:

Alborosie3 years ago

8 0

Answer: The correct answer is Option D.

Explanation:

For the given chemical reaction:

$H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$

Catalyst is a chemical substance which alters the rate of the reaction and does not participate in the reaction. It does not effect the equilibrium position.

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle. This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

Change in volume:

Any change in volume during equilibrium is studied on the basis of change in moles of gaseous reactants and gaseous products.

When volume is decreased, the equilibrium will shift in the direction which produces fewer moles of gas and when volume is increased, the equilibrium will shift in the direction which produces more moles of gas.

Change in pressure:

Any change in pressure during equilibrium is studied on the basis of change in moles of gaseous reactants and gaseous products.

When pressure is decreased, the equilibrium will shift in the direction, which produces fewer moles of gas and when pressure is increased, the equilibrium will shift in the direction which produces more moles of gas.

Number of moles of gases on reactant side = [1 + 1] = 2

Number of moles of gases on product side = 2

Change in number of moles = 2 -2 = 0

As, number of moles on both the side of the reaction is same. This means there will be no effect on change in volume and change in pressure.

Change in temperature:

For an exothermic reaction, heat is released during a chemical reaction and is written on the product side.

$A\rightleftharpoons B+\text{ heat}$

As, heat is released during a chemical reaction. This means that temperature is decreased on the reactant side. If the temperature in the equilibrium is decreased, the equilibrium will shift in the direction where, temperature is getting increased. Thus, the reaction will shift in right direction that is towards the product.

So, lowering the temperature of the system will shift the position of equilibrium.

Hence, the correct answer is Option D.

You might be interested in

PLEASE HELP :)) WILL GIVE BRAINLIEST

hjlf

Answer:

the answer is true

5 0

3 years ago

What are fossils? *

Katarina [22]

Answer:

mark me as the brainliest

Explanation:

Fossils are the preserved remains, or traces of remains, of ancient organisms. Fossils are not the remains of the organism itself! They are rocks. A fossil can preserve an entire organism or just part of one. Bones, shells, feathers, and leaves can all become fossils.

8 0

4 years ago

Read 2 more answers

In which of the following processes will delta S be negative? Select one from above

Alona [7]

Answer:

CO2 (s) -->Co2 (g) will be the answer

3 0

3 years ago

Now, Johnny the pool guy must add enough Na2CO3 to get the pH back up to 7.60. How many grams of Na2CO3 does Johnny need to add

vaieri [72.5K]

Answer:

m = 3.4126 g

Explanation:

First, the question is incomplete but I already put in the comments the rest of the question.

Let's solve the first two questions, and then the actual question you are asking here to give you a better explanation of how to do it.

1) We need the volume of the pool, in this case is easy. Assuming the pool is rectangular, we use the volume of a parallelepiped which is the following:

V = h * d * w

We have the data, but first we will convert the feet to centimeter. This is because is easier to work the volume in cm³ than in feet.

So the height, width and depth of the pool in centimeter are:

h = 32 * 30.48 = 975.36 cm

w = 18 * 30.48 = 548.64 cm

d = 5.3 * 30.48 = 161.54 cm

Now the volume:

V = 975.36 * 548.64 * 161.54

V = 86,443,528.79 cm³ or 86,443,528.79 mL or 86,443.5 L

2) If the pool has a pH of 6.4, the concentration of H+ can be calculated with the following expression:

[H+] = antlog(-pH) or 10^(-pH)

Replacing we have:

[H+] = 10^(-6.4)

[H+] = 3.98x10^-7 M

3) Finally the question you are asking for.

According to the reaction:

Na2CO3 + H+ → 2Na+ + HCO3−

We can see that there is ratio of 1:1 between the H+ and the Na2CO3, so, if we have initially a concentration of 3.98x10^-7 M, the difference between the new concentration of H+ and the innitial, will give the concentration to be added to the pool to raise the pH. Then, with the molecular weight of Na2CO3 (105.98 g/mol) we can know the mass needed.

The new concentration of [H+] is:

[H+] = 10^(-7.6) = 2.58x10^-8 M

The difference of both [H+] will give concentration of Na2CO3 used:

3.98x10^-7 - 2.58x10^-8 = 3.73x10^-7 M

The moles:

moles = 3.73x10^-7 * 86,443.5 = 0.0322 moles

Finally the mass:

m = 0.0322 * 105.98

m = 3.4126 g

5 0

3 years ago

Given the unbalanced equation: N2(g) + H2(g) → NH3(g)

mario62 [17]

Answer:

Option-4 (3:2) is the correct answer.

Explanation:

Following steps are taken to balance the given unbalanced chemical equation.

Step 1: Write the unbalanced chemical equation,

N₂ + H₂ → NH₃

Step 2: Balance Nitrogen Atoms;

There are 2 nitrogen atoms on left hand side and 1 nitrogen atoms on right hand site therefore, to balance them multiply NH₃ on right hand side by 2 i.e.

N₂ + H₂ → 2 NH₃

Step 3: Balance Hydrogen Atoms;

Now, there are 2 hydrogen atoms on left hand side and 6 hydrogen atom on right hand site therefore, to balance them multiply H₂ on left hand side by 3 i.e.

N₂ + 3 H₂ → 2 NH₃

Now, the equation is balanced.

Step 4: Finding out mole ratios:

From balanced chemical equation it can be concluded that 3 moles of H₂ are involved in producing 2 moles of NH₃ hence, the mole ratio of consumption of H₂ to production of NH₃ is 3:2.

3 0

3 years ago