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In-s [12.5K]
3 years ago
6

H2 and I2 react in an exothermic reaction according to the following equation:

Chemistry
1 answer:
Alborosie3 years ago
8 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

For the given chemical reaction:

H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

Catalyst is a chemical substance which alters the rate of the reaction and does not participate in the reaction. It does not effect the equilibrium position.

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle. This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

  • <u>Change in volume:</u>

Any change in volume during equilibrium is studied on the basis of change in moles of gaseous reactants and gaseous products.

When volume is decreased, the equilibrium will shift in the direction which produces fewer moles of gas and when volume is increased, the equilibrium will shift in the direction which produces more moles of gas.

  • <u>Change in pressure:</u>

Any change in pressure during equilibrium is studied on the basis of change in moles of gaseous reactants and gaseous products.

When pressure is decreased, the equilibrium will shift in the direction, which produces fewer moles of gas and when pressure is increased, the equilibrium will shift in the direction which produces more moles of gas.

Number of moles of gases on reactant side = [1 + 1] = 2

Number of moles of gases on product side = 2

Change in number of moles = 2 -2 = 0

As, number of moles on both the side of the reaction is same. This means there will be no effect on change in volume and change in pressure.

  • <u>Change in temperature:</u>

For an exothermic reaction, heat is released during a chemical reaction and is written on the product side.

A\rightleftharpoons B+\text{ heat}

As, heat is released during a chemical reaction. This means that temperature is decreased on the reactant side. If the temperature in the equilibrium is decreased, the equilibrium will shift in the direction where, temperature is getting increased. Thus, the reaction will shift in right direction that is towards the product.

So, lowering the temperature of the system will shift the position of equilibrium.

Hence, the correct answer is Option D.

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What is the element of lowest atomic number whose electronic configuration has four completely filled p sub shells
disa [49]

The element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe with electron configuration:1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.

According to the question, we are required to identify the element with the lowest atomic number whose electronic configuration has four completely filled p sub-shells.

Evidently, the shell with energy level one has no p orbital.

  • Therefore, the existence of p orbitals in electron configuration begins with shell energy level, n=2.

  • However, we must know that the p-orbital comprises of 3 sub-orbitals namely;

p(x) , p(y) and p(z) with two electrons of opposing spin in each sub orbital.

  • Therefore, the total number of electrons in the p orbital is 6 electrons.

In essence, the element in question should have electron configuration;

  • 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p⁶.

The electron configuration above contains 54 electrons and has atomic number, 54.

In essence, the element of lowest atomic number whose electron configuration has 4 completely filled p orbitals is, Xenon, Xe.

Read more:

brainly.com/question/2183111

6 0
3 years ago
Balance the following equation by providing the correct coefficients C2H6 + O2 -&gt; CO2 + H2O
pogonyaev
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7 0
3 years ago
Calculate the pka of hypochlorous acid. The ph of a 0.015 m solution of hypochlorous acid has a ph of 4.64.
o-na [289]

Answer:

  • pKa = 7.46

Explanation:

<u>1) Data:</u>

a) Hypochlorous acid = HClO

b) [HClO} = 0.015

c) pH = 4.64

d) pKa = ?

<u>2) Strategy:</u>

With the pH calculate [H₃O⁺], then use the equilibrium equation to calculate the equilibrium constant, Ka, and finally calculate pKa from the definition.

<u>3) Solution:</u>

a) pH

  • pH = - log [H₃O⁺]

  • 4.64 = - log [H₃O⁺]

  • [H_3O^+]= 10^{-4.64} = 2.29.10^{-5}

b) Equilibrium equation: HClO (aq) ⇄ ClO⁻ (aq) + H₃O⁺ (aq)

c) Equilibrium constant: Ka =  [ClO⁻] [H₃O⁺] / [HClO]

d) From the stoichiometry: [CLO⁻] = [H₃O⁺] = 2.29 × 10 ⁻⁵ M

e) By substitution: Ka = (2.29 × 10 ⁻⁵ M)² / 0.015M = 3.50 × 10⁻⁸ M

f) By definition: pKa = - log Ka = - log (3.50 × 10 ⁻⁸) = 7.46

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4 years ago
If 10.5-g of Na2SO4 are actually recovered experimentally, that is the percent yield?
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<span>"If they recover 10.5 it means you shall add with the limiting 10.8, giving you 21.3g out of 142 times 100, giving 15%, I believe."
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</span>
5 0
3 years ago
Draw the other possible resonance structure of each organic ion. In each case, draw the structure that minimizes formal charges.
pshichka [43]

Three resonance structures  can be drawn for the allyl cation while two resonance structures can be drawn for the amidate ion.

Sometimes, we cannot fully describe the bonding in a chemical specie using a single chemical structure. In such cases, we have to use a number of structures which cooperatively represent the actual bonding in the molecule. These structures are called resonance or canonical structures.

The resonance structures of the allyl cation and the amidate ion are shown in the images attached to this answer. These structures show the different bonding extremes in these organic ions.

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7 0
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