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Sholpan [36]
3 years ago
6

The density of Silver is 10.5 g/mL. How much mass would be present given a silver cube

Chemistry
1 answer:
seraphim [82]3 years ago
3 0

Answer:

m=dxv

= 10.5 x 965 = 10132.5 rounded off to 10100 g

Explanation:

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D. reproductive cells uwu
3 0
3 years ago
What is the temperature change if 400 J of energy is added to 10 grams of water
Gemiola [76]

The temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.

<h3>How to calculate temperature change?</h3>

The temperature change of a calorimeter can be calculated using the following expression:

E = mc∆T

Where;

  • E = energy in joules
  • m = mass
  • c = specific heat capacity = 4.18J/g°C
  • ∆T = change in temperature

400 = 10 × 4.18 × ∆T

400 = 41.8∆T

∆T = 400/41.8

∆T = 9.57°C

Therefore, the temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.

Learn more about change in temperature at: brainly.com/question/11464844

3 0
3 years ago
2NaClO3 ——&gt; 2NaCl + 3O2
Alborosie

Answer:  

<h3>1) 208.09 g</h3><h3>2) 7.11 × 10²² particles</h3>

<h2>Explanation:</h2><h3>NUMBER ONE</h3>

<u>Find moles of Known Substance (NaCl)</u>

Moles of NaCl = mass ÷ molar mass

                        =  114.25 g ÷ 58.44 g/mol

                        = 1.955 mol

<u>Use Mole Ratio of Known to Unknown (NaCl : NaClO₃) to Determine Moles of Unknown</u>

The mole ratio of NaCl to NaClO₃ is 2 to 2 or simply 1 to 1.

This means that for each mole of NaCl produced the same number of moles of NaClO₃ was decomposed.

∴ since moles of NaCl = 1.955 mol,

then moles of NaClO₃ = 1.955 mol

<u>Find Mass of Unknown </u>

Mass of NaClO₃ = moles × molar mass

                           = 1.955 mol × 106.44 g/mol

                           =  208.09 g

<h3>NUMBER TWO</h3>

<u>Determine the Moles of Known (O₂)</u>

moles of O₂ = (volume × density) ÷ molar mass

                    = (68.30 L × 0.0828 g/L) ÷ 32 g/mol

                    = 0.177 mol

<u>Use Mole Ratio of Known to Unknown (O₂ : NaClO₃) to Determine Moles of Unknown</u>

Mole ratio of O₂ : NaClO₃ is 3 : 2. Therefore for each mole of oxygen produced, ²/₃ the moles of NaClO₃ is produced.

∴ if moles of O₂  =  0.177 mol

then moles of NaClO₃ =  0.177 mol × ²/₃

                                     = 0.118 mol

<u>Find the Number of Particles of Unknown</u>

Number of particles  = moles × Avogadro's Number

                                  = 0.118 mol × (6.022 × 10²³ particles/mol)

                                  =  7.11 × 10²² particles

3 0
3 years ago
15 moles of an ideal gas at STP has a volume of ____liters
S_A_V [24]

Answer:

A. 336 L

Explanation:

STP is 0 °C and 1 bar.

At STP, the molar volume of a gas is 22.71 L.

Volume = 15 mol × 22.71 L/mol

Volume = 341 L

===============

The above answer is not in your list of options.

It appears that you are using the <em>OLD</em> (pre-1982) definition of STP, at which the molar volume of a gas is 22.4 L.

Then

V = 15 mol × 22.4 L/mol = 336 L

4 0
3 years ago
How many grams of CaCl2would be dissolved in 1.0 L of a 0.10M<br> solution of CaCl2?
Goryan [66]
Mass of CaCl2=11g
I hope this one is help you

3 0
3 years ago
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