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ddd [48]
3 years ago
8

1. An ideal gas undergoes a process according to PV" = k. Initially, the temperature and volume are 2 bar and 0.1m?, respectivel

y. After the process, the volume doubles. Determine the work done during the process. Take n = 1.4 ​
Engineering
1 answer:
ella [17]3 years ago
8 0
Tryna boost my score for college stuff could you give me the brainiest and a thanks? Hope you find your answer your looking for!
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A pipe leads from a storage tank on the roof of a building to the ground floor. The absolute pressure of the water in the storag
Fudgin [204]

Answer:

6.4 m/s

Explanation:

From the equation of continuity

A1V1=A2V2 where A1 and V1 are area and velocity of inlet respectively while A2 and V2 are the area and velocity of outlet respectively

A1=\pi (r1)^{2}

A2=\pi (r2)^{2}

where r1 and r2 are radius of inlet and outlet respectively

v1 is given as 1.6 m/s

Therefore

\pi (0.01)^{2}\times 1.6 = \pi (0.005)^{2}v2

V2=\frac {\pi (0.01)^{2}\times 1.6}{\pi (0.005)^{2}}=6.4 m/s

3 0
4 years ago
Who plays warzone ps4?
dsp73
Who doesn’t play war zone
7 0
3 years ago
Read 2 more answers
The Reynolds number for flow over a fixed horizontal flat plate is constant throughout its length. a) True b) False
ANTONII [103]

Answer: False

Explanation: Reynolds number is the number for determining he flow pattern of the behavior of fluids.It judges the flow of the fluid ans states whether it is of turbulent or laminar natured. This number has the property of kinematics as well as statics. It can also be defined as the ratio between the inertial force to viscous force.It's length changes along with change length of the horizontal plate .Thus, the statement given is false.

5 0
4 years ago
Assume we have one road section which has 3 lanes in both directions. If the Sf for both direction is 75 mph, and Dj for both di
givi [52]

Answer:

i) 3750 veh/hr/ln

ii) 100 veh/mi/In

iii) 37.5 mph

Explanation:

number of lanes = 3

sf for both directions = 75 mph  ( free mean speed )

Dj for both directions = 200 veh/mi/In

<u>Calculate the value of  S0, D0 (veh/mi/ln) and maximum Vm (veh/hr)</u>

For either direction we will consider the total volume = 3 lanes

value of Dj = 3 lanes * 200 = 600 veh/mi/

i) value of SO

=  ( Dj * sf ) / 4 = ( 600 * 75 ) / 4 = 11250 veh/hr  = 3750 veh/hr/lane

ii) Value of DO

DO = Dj / 2 = 200 /2 = 100 veh/mi/In

iii) Value of Vm

= sf /2 = 75 / 2 = 37.5 mph

5 0
3 years ago
Write a Lottery class that simulates a lottery. The class should have an array of five integers named lotteryNumbers. The constr
Bezzdna [24]

Answer:

Output:-

Enter the five digit lottery number

Enter the digit 1 : 23

Enter the digit 2 : 44

Enter the digit 3 : 43

Enter the digit 4 : 66

Enter the digit 5 : 33

YOU LOSS!!

Computer Generated Lottery Number :

|12|38|47|48|49|

Lottery Number Of user:

|23|33|43|44|66|

Number Of digit matched: 0

Code:-

import java.util.Arrays;

import java.util.Random;

import java.util.Scanner;

public class Lottery {

int[] lotteryNumbers = new int[5];

public int[] getLotteryNumbers() {

return lotteryNumbers;

}

Lottery() {

Random randomVal = new Random();

for (int i = 0; i < lotteryNumbers.length; i++) {

lotteryNumbers[i] = randomVal.nextInt((50 - 1) + 1);

}

}

int compare(int[] personLottery) {

int count = 0;

Arrays.sort(lotteryNumbers);

Arrays.sort(personLottery);

for (int i = 0; i < lotteryNumbers.length; i++) {

if (lotteryNumbers[i] == personLottery[i]) {

count++;

}

}

return count;

}

public static void main(String[] args) {

int[] personLotteryNum = new int[5];

int matchNum;

Lottery lnum = new Lottery();

Scanner input = new Scanner(System.in);

System.out.println("Enten the five digit lottery number");

for (int i = 0; i < personLotteryNum.length; i++) {

System.out.println("Enter the digit " + (i + 1) + " :");

personLotteryNum[i] = input.nextInt();

}

matchNum = lnum.compare(personLotteryNum);

if (matchNum == 5)

System.out.println("YOU WIN!!");

else

System.out.println("YOU LOSS!!");

System.out.println("Computer Generated Lottery Number :");

System.out.print("|");

for (int i = 0; i < lnum.getLotteryNumbers().length; i++) {

System.out.print(lnum.getLotteryNumbers()[i] + "|");

}

System.out.println("\n\nLottery Number Of user:");

System.out.print("|");

for (int i = 0; i < personLotteryNum.length; i++) {

System.out.print(personLotteryNum[i] + "|");

}

System.out.println();

System.out.println("Number Of digit matched: " + matchNum);

}

}

Explanation:

5 0
3 years ago
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