a) time, t = 11.407 s, b) distance x = 175.66 m, v = c) speed v = 30.80 m / s
<h3>Explanation of question:</h3>
a) This is kinematics exercise, write the equation of each vehicle car is;-
x = x₀ + v₀ t + ½ a t²
Let's fix our the reference system at a point where the car indicate that the car stops from rest is vo = 0.
x₀ = v₀ = 0
<h3>we substitute</h3>
x = ½ a t²
truck
x₂= v₀ t
v₀ = 15.4 m / s
At the point where they are, positions are equal:-
½ a t² = vo t
t = 2 vo / a
calculate us
t = 2 15.4 / 2.
t = 11.407 s
b) the distance to reach it
x = ½ to t²
x = ½ 20 11.407²
x = 175.66 m
c) the speed of the car is
v = vo + a t
vo = 0
v = at
v = 2.0 11.407
v = 30.80 m / s
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<span> 4. 1 and 2 only.
1. the downward force is the force of gravity.
2. The upward force exerted is the Normal reaction from the floor.
</span>
Answer:
An acid is a compound that increases hydrogen ions (H+) when it is dissolved in a solution.
all I got
Answer:
0 J
Explanation:
From the diagram below; we would notice that the Force (F) = Tension (T)
Also the angle θ adjacent to the perpendicular line = 90 °
The Workdone W = F. d
W = Fd cos θ
W = Fd cos 90°
W = Fd (0)
W = 0 J
Hence the force is perpendicular to the direction of displacement and the net work done in a circular motion in one complete revolution is = 0
I think it's C. if we're talking about a rover.
But if it's a rocket that's computerized and automatic (synonym of unmanned)... Then it's B.
