Answer:
the answer would be "using more heat" btw
Explanation:
<h2>
Hello!</h2>
The answer is:
The buoyant force is equal to 49N.
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Why?</h2>
The buoyant force is the force that pushes upwards and object when it's submerged in water, this force is always trying to move the object to the surface of the liquid or water. We must consider that the volume of water or liquid displaced is equal to the volume of the submerged object.
We can calculate the buoyant force using the following formula:

Where,
Density is the density of the water or liquid.
Volume displaced is equal to the volume of the submerged object.
Gravity acceleration is the acceleration due to gravity.
So, from the statement we know that:

Now, substituting and calculating we have:




Hence, we have that the correct answer is:
The buoyant force is equal to 49N.
Have a nice day!
Complete Question
(A) What is the maximum tension possible in a 1.00- millimeter-diameter nylon tennis racket string?
(B) If you want tighter strings, what do you do to prevent breakage: use thinner or thicker strings? Why? What causes strings to break when they are hit by the ball?
The tensile strength of the nylon string is 
Answer:
A
T = 471.3 \ N
B
To prevent breakage the thickness of the string is increased
String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension
Explanation:
From the question we are told that
The diameter is
The tensile strength of the nylon string is 
Generally the radius is mathematically evaluated as

=> 
=> 
The cross sectional area is mathematically represented as

=> 
=> 
Generally the tensile strength of nylon is mathematically represented as

Where T is the tension on the maximum tension on the string
So

=> 
=> 
Form the equation above we see that

So if the tension is increased to prevent breakage the thickness of the string is increased(i. e the cross-sectional area )
String breakage when the racket hit the ball is as a result of the string not being thick enough to withstand the increase in tension
Oh my gosh had the same question