Answer:
0.104 M
Explanation:
For the titration of an acid and a base , the relation between the molarity and volume is as follows -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base ,
V₂ = Volume of base ,
from , the question ,
M₁ = ?
V₁ = 50.0 mL
M₂ = 0.1510 M
V₂ = 34.62 mL
Using the above formula , the molarity of the stock solution , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 50.0 mL = 0.1510 M * 34.62 mL
M₁ = 0.1510 M * 34.62 mL / 50.0 mL
M₁ = 0.104 M
Moles: 3.5185010135335 is the answer i believe
Answer:
are you kidding how old are you
Answer:
55.1 g Si.
Explanation:
Hello there!
In this case, for the given mole-mole relationship, it is possible to set up the following mole ratio as the moles of Si and P are the same:
1 mol Si = 1 mol P.
Next, since one mole of silicon has a mass of 28.09 g and one of phosphorous of 31.0 g, we can set up the following expression for the mass of silicon:
Therefore, the result is 55.1 grams of silicon.
Best regards!
The statement that best describes waves is B. Waves cannot propagate without a medium