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UNO [17]
3 years ago
11

Find the length of the third side of the triangle.

Physics
1 answer:
AlladinOne [14]3 years ago
4 0

Answer:

v

Image result for What is the length of the hypotenuse of the triangle below

One way to solve this is to use Pythagorean theorem: the square of one leg of triangle plus square of other leg of the triangle equals c the hypotenuse (longest side of triangle). You might see this as the formula a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse.Nov 23, 2016

Explanation:

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What is the magnetic force (in newtons) on a particle traveling in a 1.5 T magnetic field if q = 7.5 microcoulombs and v = 1.75
Alla [95]

Given:

B(Magnetic field): 1.5 T                                                                                

q=  7.5 microcoulombs                                                                                

v= 1.75 x 10 ∧6 m/s                                                                                    

The angle ∅ between B and v is 45 °.                                                    

Now we know that F= qvB sin ∅

Substituting these values we get:

F= 7.5 x 10∧-6 x 1.75 x 10∧6 x 1.5 x sin 45                                                

 F= 16.752 N



3 0
3 years ago
10. How much work is done by gravity if it pulls a 100 N object down 2 m?
NeTakaya

Answer:

200 J

Explanation:

W = f * d

W = 100N * 2m

W = 200 J

5 0
3 years ago
A 4.0 cm object is 6.0 cm from a convex mirror that has a focal length of 8.0 cm. What is the distance of the image from the mir
ioda

Mirror formula

1/f = (1/p) + (1/q)    [ f= focal length  ,  p= object distance ,  q = image distance ]

as given convex mirror so

distance of object =p= 6cm

focal length =  -8cm

to find q=?

1/q =( 1/f) - (1/ p)

1/q = (1/ 8) -(1/6)

1/q =-1/24

q=-24  ( negative sign shows image is virtual and behind the mirror)

5 0
4 years ago
A sample of chloroform is found to contain 12.0 g of carbon, 106.4 g of chlorine, and 1.01 g of hydrogen. If a second sample of
GREYUIT [131]

Given:

Sample 1:

Chloroform is CHCl_{3}

12 g Carbon

1.01 g Hydrogen

106.4 g Cl

Sample 2:

30.0 g of Carbon

Solution:

mass of chloroform from sample 1:

12 + 1.01 +106.4 =119.41 g

Now, for the total mass of chloroform in sample 2:

mass of chloroform \times\frac{given mass of carbon}{mass of carbon atom}

mass of chloroform = 119.41 \times\frac{30}{12} = 298.53 g

6 0
3 years ago
You could make an air purifier by pumping air through a region that has an electric field. What kinds of particles would you be
Lina20 [59]

Answer:

We can remove ions and water molecules

Explanation:

We can remove ions and water molecules because both of them have an electric field . So this will help in repelling or attractive the above mentioned particles. Water is polar so it has an electric field due to net dipole moment.

6 0
3 years ago
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