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3 years ago

Find the length of the third side of the triangle.

Physics

1 answer:

AlladinOne [14]3 years ago

4 0

Answer:

Image result for What is the length of the hypotenuse of the triangle below

One way to solve this is to use Pythagorean theorem: the square of one leg of triangle plus square of other leg of the triangle equals c the hypotenuse (longest side of triangle). You might see this as the formula a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse.Nov 23, 2016

Explanation:

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A 47.2 kg girl is standing on a 177 kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat,

Softa [21]

Answer:

v_g,i = 1.208 m/s

Explanation:

We are given;

Mass of girl; m_g = 47.2 kg

Mass of plank; m_p = 177 kg

Let the velocity of girl to ice be v_g,i

Let the velocity of plank to ice be v_p,i

Since the velocity of the girl is 1.53 m/s relative to the plank, then;

v_g,i + v_p,i = 1.53

From conservation of momentum;

m_g × v_g,i = m_p × v_p,i

Thus;

47.2(v_g,i) = 177(v_p,i)

Dividing both sides by 47.2 gives;

v_g,i = 3.75(v_p,i)

v_pi = (v_g,i)/3.75

Thus, from v_g,i + v_p,i = 1.53, we have;

v_g,i + ((v_g,i)/3.75) = 1.53

v_g,i(1 + 1/3.75) = 1.53

1.267v_g,i = 1.53

v_g,i = 1.53/1.267

v_g,i = 1.208 m/s

5 0

3 years ago

Firefighters are holding a nozzle at the end of a hose while trying to extinguish a fire. If the nozzle exit diameter is 8 cm an

kobusy [5.1K]

Answer:

Answer for the question is given in the attachment.

Explanation:

5 0

3 years ago

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What is a chunk of space rock

Igoryamba

The answer to your question is,

A meteoroid.

-Mabel <3

7 0

3 years ago

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Calculate the electrical force that acts on one plate of a parallel plate capacitor. The potential difference between the plates

eduard

Answer:

The work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.

Explanation:

Given;

potential difference between the plates, V = 10 V

length of each square side of the plates, L = 20 cm = 0.2 m

area of the plates, A = 0.2 x 0.2 = 0.04 m²

separation of the plates, d = 3 cm = 0.03 m

The work done in bringing the plates together is calculated as;

W = ¹/₂qV

$W = \frac{1}{2} (\frac{\epsilon_0 A }{d}V) \times V\\\\W = \frac{\epsilon_0 A V^2}{2d}\\\\W = \frac{8.85 \times 10^{-12} \ \times \ 0.04\ \times \ 10^2}{2(0.03)} \\\\W = 5.9 \times 10^{-10} \ J$

Therefore, the work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.

8 0

2 years ago

A 2.80 kg mass is dropped from a height of 4.50 m. Find its potential energy when it reaches the ground.

marshall27 [118]

Answer:

123.48J

Explanation:

Given parameters:

Mass of the ball = 2.8kg

Height = 4.5m

Unknown:

Potential energy = ?

Solution:

The potential energy is the energy due to the position of a body. It is mathematically given as;

P.E = mgh

m is the mass

g is the acceleration due to gravity

h is the height

Now insert the parameters and solve;

P.E = 2.8 x 4.5 x 9.8 = 123.48J

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3 years ago

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