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anzhelika [568]
3 years ago
8

The atomic number is the same as the number of ________.

Chemistry
1 answer:
Zanzabum3 years ago
5 0

Answer:

number of electrons

Explanation:

(happy to help)

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Work your way from years to months to days to hours to minutes to seconds.
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3 years ago
The solid rocket boosters for the space shuttle employ a mixture of aluminum and ammonium perchlorate (molar mass = 117 g/mol) a
Mnenie [13.5K]

Answer : The volume of gas at STP produced are 45.0 L

Explanation :

First we have to calculate the moles of ammonium perchlorate.

\text{Moles of }NH_4ClO_4=\frac{\text{Mass of }NH_4ClO_4}{\text{Molar mass of }NH_4ClO_4}

Molar mass of NH_4ClO_4 = 117 g/mole

\text{Moles of }NH_4ClO_4=\frac{235g}{117g/mole}=2.01mole

Now we have to calculate the moles of NO gas produced during the reaction.

The balanced chemical reaction is,

3Al(s)+3NH_4ClO_4(s)\rightarrow Al_2O_3(s)+AlCl_3(s)+3NO(g)+6H_2O(g)

From the reaction we conclude that,

As, 3 moles of NH_4ClO_4 produces 3 moles of NO gas

So, 2.01 moles of NH_4ClO_4 produces 2.01 moles of NO gas

Now we have to calculate the volume of gas at STP.

At STP, 1 mole of substance occupy 22.4 L volume of gas.

As, 1 mole of NO gas occupy 22.4 L volume of gas.

So, 2.01 mole of NO gas occupy 2.01 × 22.4 L = 45.0 L volume of gas.

Therefore, the volume of gas at STP produced are 45.0 L

6 0
4 years ago
What is the name of this molecule?<br> A.Butane<br> B.Butene<br> C.Propene<br> D.Propane
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The answer is D, Propane
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4 years ago
What is the mass number for the neutral atom shown in the diagram below?
eduard

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7 0
3 years ago
Given the following amounts of gasses, calculate the number of moles of each gas. Calculate the volume of each amount of gas wou
barxatty [35]

Answer:

a) V = 0.6958 L

b) V = 3.061 L

c) V = 0.0444L

Explanation:

<em>a)  5.8 grams of NH3</em>

step 1: Calculate moles of NH3

Moles NH3 = mass NH3 / molar mass of NH3

Moles NH3 = 5.8 grams / 17.03 g/mol

Moles NH3 = 0.341 moles

step 2: Calculate volume of NH3

p*V = n*R*T

V = (nRT)/p

V = (0.341 * 0.08206 * 373)/15

V =0.6958 L

<em>b) 48g O2</em>

step 1: Calculate moles of O2

Moles O2 = mass O2 / molar mass of O2

Moles O2 = 48 grams / 32 g/mol

Moles NH3 = 1.5 moles

step 2: Calculate volume of O2

p*V = n*R*T

V = (nRT)/p

V = (1.5 * 0.08206 * 373)/15

V =3.061 L

<em>c) 10.8g He</em>

step 1: Calculate moles of He

Moles He = mass He / molar mass of He

Moles He = 5.8 grams / 4g/mol

Moles He = 0.145 moles

step 2: Calculate volume of HE

p*V = n*R*T

V = (nRT)/p

V = (0.145 * 0.08206 * 373)/15

V =0.0444 L

4 0
3 years ago
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