The correct one is A. Technician Only.
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Answer:
Angular velocity (w) = 8.86 rad/s
Explanation:
Angular velocity (w) = ![\sqrt{} 4ghi/R^{2}](https://tex.z-dn.net/?f=%5Csqrt%7B%7D%204ghi%2FR%5E%7B2%7D)
g= 9.81 m/s
R= 0.5
hi (initial depth) = 0.5m
Hence=
= 8.86 rad/s
Answer:
The normal force will be lower than the gravitational force acting on the car. Therefore the answer is N < mg, which is <em>option B</em>.
Explanation:
Over a round hill, the centripetal force acting toward the the radius of the hill supports the gravitational force (mg) of the car. This notion can be expressed mathematically as follows:
At the top of a round hill
![Normal force = Gravitational force - centripetal force](https://tex.z-dn.net/?f=Normal%20force%20%3D%20Gravitational%20force%20-%20centripetal%20force)
At the foot of a round hill
![Normal Force = centripetal force + Gravitational force](https://tex.z-dn.net/?f=Normal%20Force%20%3D%20centripetal%20force%20%2B%20Gravitational%20force)
Explanation:
The electric field at a distance r from the charged particle is given by :
![E=\dfrac{kq}{r^2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bkq%7D%7Br%5E2%7D)
k is electrostatic constant
if r = 2 m, electric field is given by :
![E_1=\dfrac{kq}{(2)^2}\\\\=\dfrac{kq}{4}\ .....(1)](https://tex.z-dn.net/?f=E_1%3D%5Cdfrac%7Bkq%7D%7B%282%29%5E2%7D%5C%5C%5C%5C%3D%5Cdfrac%7Bkq%7D%7B4%7D%5C%20.....%281%29)
If r = 1 m, electric field is given by :
![E_2=\dfrac{kq}{r_2^2}\\\\=\dfrac{kq}{1}\ ....(2)](https://tex.z-dn.net/?f=E_2%3D%5Cdfrac%7Bkq%7D%7Br_2%5E2%7D%5C%5C%5C%5C%3D%5Cdfrac%7Bkq%7D%7B1%7D%5C%20....%282%29)
Dividing equation (1) and (2) we get :
![\dfrac{E_1}{E_2}=\dfrac{\dfrac{kq}{4}}{kq}\\\\\dfrac{E_1}{E_2}=\dfrac{1}{4}\\\\E_2=4\times E_1](https://tex.z-dn.net/?f=%5Cdfrac%7BE_1%7D%7BE_2%7D%3D%5Cdfrac%7B%5Cdfrac%7Bkq%7D%7B4%7D%7D%7Bkq%7D%5C%5C%5C%5C%5Cdfrac%7BE_1%7D%7BE_2%7D%3D%5Cdfrac%7B1%7D%7B4%7D%5C%5C%5C%5CE_2%3D4%5Ctimes%20E_1)
So, at a point 1 m from the particle, the electric field is 4 times of the electric field at a point 2 m.
Answer:
The minimum wall thickness required for the spherical tank is 0.0189 m
Explanation:
Given data:
d = inside diameter = 8.1 m
P = internal pressure = 1.26 MPa
σ = 270 MPa
factor of safety = 2
Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?
The allow factor of safety:
![\sigma _{a} =\frac{\sigma }{factor-of-safety} =\frac{270}{2} =135MPa](https://tex.z-dn.net/?f=%5Csigma%20_%7Ba%7D%20%20%3D%5Cfrac%7B%5Csigma%20%7D%7Bfactor-of-safety%7D%20%3D%5Cfrac%7B270%7D%7B2%7D%20%3D135MPa)
The minimun wall thickness:
![t=\frac{Pd}{4\sigma _{a} } =\frac{1.26*8.1}{4*135} =0.0189m](https://tex.z-dn.net/?f=t%3D%5Cfrac%7BPd%7D%7B4%5Csigma%20_%7Ba%7D%20%7D%20%3D%5Cfrac%7B1.26%2A8.1%7D%7B4%2A135%7D%20%3D0.0189m)