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aliya0001 [1]
3 years ago
12

Which term best describes a fad diet

Physics
1 answer:
stira [4]3 years ago
6 0

Answer:

a fad diet is basically a diet that was a trend or that was popular for a short amount of time and makes unreasonable claims for fast and very much wanted results

Explanation:

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A bird is traveling west with a velocity of 8 m/s and momentum of 40 mg*m/s what's the birds mass?
VikaD [51]

Answer:

m = 5 [mg]

Explanation:

We must remember that the definition of linear momemtum is defined as the product of mass by distance.

P = m*v

P = momentum = 40 [mg*m/s]

m = mass [mg]

v = velocity = 8 [m/s]

Now clearing m:

m = P/v

m = 40/8

m = 5 [mg]

3 0
3 years ago
a car is traveling north on the interstate. They cover 645 miles in 9 hours. What is the car's average velocity ?
kow [346]
71.66 miles per hour
7 0
3 years ago
Read 2 more answers
Sally takes two bar magnets and randomly tapes one end of each bar magnet. she labels the magnets A and B. She brings the taped
vlabodo [156]
Since the two taped poles of the magnets labeled A and B attracts one to each other, we know that the two taped poles are oppsosite.

So, you can predict with total certainty that when she brings the taped end of the third magnet (magnet C) near each of the first two magntes, in one case they will attract each other and in the other case they will repele mutually.

You are certain of that because, since the taped poles of the first two magnets are opposite, the pole of the third magnet has to be equal to one of the two first taped poles and opposite to the other of the two firest taped poles.
8 0
3 years ago
Suppose that in a lightning flash the potential difference between a cloud and the ground is 0.96×109 V and the quantity of char
Dvinal [7]

(a) 2.98\cdot 10^{10} J

The change in energy of the transferred charge is given by:

\Delta U = q \Delta V

where

q is the charge transferred

\Delta V is the potential difference between the ground and the clouds

Here we have

q=31 C

\Delta V = 0.96\cdot 10^9 V

So the change in energy is

\Delta U = (31 C)(0.96\cdot 10^9 V)=2.98\cdot 10^{10} J

(b) 7921 m/s

If the energy released is used to accelerate the car from rest, than its final kinetic energy would be

K=\frac{1}{2}mv^2

where

m = 950 kg is the mass of the car

v is the final speed of the car

Here the energy given to the car is

K=2.98\cdot 10^{10} J

Therefore by re-arranging the equation, we find the final speed of the car:

v=\sqrt{\frac{2K}{m}}=\sqrt{\frac{2(2.98\cdot 10^{10})}{950}}=7921 m/s

5 0
3 years ago
PLEASE HELP can not find the answer
romanna [79]
I think the answer would be letter B.
7 0
3 years ago
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