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aniked [119]
3 years ago
9

Chlorine (cl) has an atomic number of 17. it often forms an ion by gaining 1 electron. what would its charge be?

Chemistry
2 answers:
vichka [17]3 years ago
8 0

Explanation:

When a neutral atom tends to gain an electron then it acquires a negative charge. Hence, an anion is formed.

For example, atomic number of chlorine is 17 and its electronic distribution is 2, 8, 7.

So, in order to attain stability it tends to gain one electron from a donor atom. Therefore, a chlorine ion is formed as Cl^{-1}.

Since, it gains only one electron that is why, -1 charge occurs. Whereas if an atom gains two electrons then it acquires a -2 charge and so on.

Thus, we can conclude that chlorine (Cl) has an atomic number of 17. It often forms an ion by gaining 1 electron. Its charge be -1.

Aliun [14]3 years ago
6 0

Answer:

= -1

Explanation:

  • Chlorine belongs to the halogen group in the periodic table. It has an atomic number of 17, which indicates the number of protons and electrons in a neutral atom of chlorine is 17.
  • Therefore; with an atomic number of 17, its electronic configuration will be 2:8:7.
  • Thus; to attain a stable configuration chlorine requires to gain one electron, by so doing it becomes a negatively charged ion with a charge of -1.
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Answer:

d. 99.63% and 0.364%, respectively

Explanation:

The average mass of a nitrogen atom is 14.006 amu

14N-14.00307 amu with 0.9963 fractional abundance

1SN- 15.000108 amu with 0.00364 fractional abundance.

The relative abundance definition in chemistry is the percentage of a particular isotope that occurs in nature. The atomic mass listed for an element on the periodic table is an average mass of all known isotopes of that element.

In this problem, the fractional abundance has areaady been given. All we need to do now is convert them to percentage abundance.

14N-14.00307 = 0.9963* 100% = 99.63%

1SN- 15.000108 = 0.00364 * 100% = 0.364%

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3 years ago
The density of helium in a balloon is 1.18 g/L. If a
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There is 3.58 He in the balloon.
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Energy is transferred from the sun to Earth mainly by
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2 years ago
If you have 30.O g of hydrogen gas burned in excess oxygen how many moles of water can you make
vladimir1956 [14]

Answer:

15 moles

Explanation:

Data given:

mass of hydrogen (H₂) = 30.0 g

amount of oxygen (O₂) = excess

moles of water = ?

Solution:

First we look to the reaction in which hydrogen react with oxygen and make (H₂O)

Reaction:

              2H₂  + O₂  -----------> 2H₂O

Now look at the reaction for mole ratio

             2H₂  + O₂  -----------> 2H₂O

             2 mole                       2 mole

So it is 2:2 mole ratio of hydrogen to water

As we Know

molar mass of H₂  = 2(1) = 2 g/mol

molar mass of H₂O = 2(1) + 16 = 18 g/mol

Now convert moles to gram

                  2H₂         +       O₂        ----------->    2H₂O

          2 mole (2 g/mol)                                 2 mole (18 g/mol)

                    4 g                                                     36 g

So,

we come to know that 4 g of hydrogen gives 36 g of water then how many grams of water will be produce by 30 grams of hydrogen.

Apply unity formula

                       4 g of H₂ ≅ 36 g of H₂O

                        30 g of H₂ ≅ X of H₂O

Do cross multiplication

                  X of H₂O =  30 g x 36 g / 4 g

                  X of H₂O =  270 g

Now convert grams of H₂O into moles

               No. of moles = mass in grams/molar mass

Put values in above formula

               No. of moles = 270 g / 18 (g/mol)

               No. of moles = 15 mol

so 30 gram of hydrogen produce 15 mol of water.

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