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Annette [7]
2 years ago
7

How might engineers use tidal data when building a bridge or a dock?

Physics
1 answer:
kifflom [539]2 years ago
7 0

Answer:

Explanation:

1) Make sure the service portion of the structure stays above the highest probable water level.

2) Make sure the support structure in contact with the water can withstand the tidal flows

3) Consider whether the added restriction of the proposed structure will altar the height of, or water velocity contained in, the tidal exchanges.

4) Consider whether a dock needs to have mechanisms to compensate for large sea level changes.

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A car and a train move together along straight, parallel paths with the same constant cruising speed v(initial). At t=0 the car
kogti [31]

Answer:

t_1 = \frac{v_i}{a_i}

t_2 = \frac{v_i}{a_i}

Δd = v_it_1 = v_i^2/a_i

Explanation:

As v(t) = v_i + at, when the car is making full stop, v(t_1) = 0 . a = -a_i . Therefore,

0 = v_i - a_it_1\\v_i = a_it_1\\t_1 = \frac{v_i}{a_i}

Apply the same formula above, with v(t_2) = v_i and a = a_i, and the car is starting from 0 speed,  we have

v_i = 0 + a_it_2\\t_2 = \frac{v_i}{a_i}

As s(t) = vt + \frac{at^2}{2}. After t = t_1 + t_2, the car would have traveled a distance of

s(t) = s(t_1) + s(t_2)\\s(t_1) = (v_it_1 - \frac{a_it_1^2}{2})\\ s(t_2) = \frac{a_it_2^2}{2}

Hence s(t) = (v_it_1 - \frac{a_it_1^2}{2}) + \frac{a_it_2^2}{2}

As t_1 = t_2 we can simplify s(t) = v_it_1

After t time, the train would have traveled a distance of s(t) = v_i(t_1 + t_2) = 2v_it_1

Therefore, Δd would be 2v_it_1 - v_it_1 = v_it_1 = v_i^2/a_i

8 0
3 years ago
An owl weighing 40N is sitting in a tree waiting to dive down to catch a mouse. If the owl's potential energy is 800 J with resp
Natali5045456 [20]

Answer:

<em>h = 20 m</em>

Explanation:

<u>Gravitational Potential Energy</u>

Gravitational potential energy (GPE) is the energy stored in an object due to its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.

The weight of an object of mass m is:

W = m.g

Thus, the GPE is:

U=W.h

Solving for h:

\displaystyle h=\frac{U}{W}

The weight of the owl is W=40 N and its GPE is U=800 J.

\displaystyle h=\frac{800}{40}=20

h = 20 m

3 0
3 years ago
Which of the following has the greatest kinetic energy? A. a mass of 4m at velocity v. B. a mass of 3m at velocity 2v. C. a mass
Artist 52 [7]

Answer:

Option C

Explanation:

Kinetic energy is the energy that the body possesses by virtue of its motion.

The formula for Kinetic energy is given by \frac{1}{2} mv^2

Using this formula let us find kinetic energy for the bodies given and find out which is the greatest

A) KE = \frac{1}{2} (4m)(v^2) = 2mv^2

B) KE =\frac{1}{2} (3m)(2v)^2 = 6mv^2

C) KE = \frac{1}{2} (2m)(3v)^2 = 9mv^2

D) KE = \frac{1}{2} (3)(4v)^2 = 8mv^2

Comparing these we find that 9mv^2 is the highest.

Hence option C is the answer.

4 0
3 years ago
What force keeps a water spider on the surface of water
DENIUS [597]
I think it's surface tension force
5 0
3 years ago
The focus of counterinsurgency (coin) operations generally progresses through three stages. which stage concerns itself with exp
posledela
The term counter-insurgency refers to the actions (political and military) that aims in targeting the activities the revolutionaries. This operation consists of three stages. The stage that focuses on the expansion of stability operations onto the opposed regions by utilizing host nation forces belongs to the middle stage. Answer is C.
4 0
3 years ago
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