Answer:
Administrative controls,
Explanation:
such as training, inspection, housekeeping and so on can be used to limit exposure.
Answer:
Using linkedlist on C++, we have the program below.
Explanation:
#include<iostream>
#include<cstdlib>
using namespace std;
//structure of linked list
struct linkedList
{
int data;
struct linkedList *next;
};
//print linked list
void printList(struct linkedList *head)
{
linkedList *t=head;
while(t!=NULL)
{
cout<<t->data;
if(t->next!=NULL)
cout<<" -> ";
t=t->next;
}
}
//insert newnode at head of linked List
struct linkedList* insert(struct linkedList *head,int data)
{
linkedList *newnode=new linkedList;
newnode->data=data;
newnode->next=NULL;
if(head==NULL)
head=newnode;
else
{
struct linkedList *temp=head;
while(temp->next!=NULL)
temp=temp->next;
temp->next=newnode;
}
return head;
}
void multiplyOddPosition(struct linkedList *head)
{
struct linkedList *temp=head;
while(temp!=NULL)
{
temp->data = temp->data*10; //multiply values at odd position by 10
temp = temp->next;
//skip odd position values
if(temp!= NULL)
temp = temp->next;
}
}
int main()
{
int n,data;
linkedList *head=NULL;
// create linked list
head=insert(head,20);
head=insert(head,5);
head=insert(head,11);
head=insert(head,17);
head=insert(head,23);
head=insert(head,12);
head=insert(head,4);
head=insert(head,21);
cout<<"\nLinked List : ";
printList(head); //print list
multiplyOddPosition(head);
cout<<"\nLinked List After Multiply by 10 at odd position : ";
printList(head); //print list
return 0;
}
Answer:
The radius of curvature is 979 meter
Explanation:
We have given velocity of the canon ball v = 98 m/sec
Acceleration due to gravity 
We know that at highest point of trajectory angular acceleration is equal to acceleration due to gravity
Acceleration due to gravity is given by 
, here v is velocity and r is radius of curvature
So 
r = 979 meter
So the radius of curvature is 979 meter
Answer:
;-;
Explanation:
am i dyslexic or is this another language
Answer:
hello your question is incomplete attached below is the complete question
A) optimum compressor ratio = 9.144
B) specific thrust = 2.155 N.s /kg
C) Thrust specific fuel consumption = 1670.4 kg/N.h
Explanation:
Given data :
Mo = 2.1 , To = 220k , Tt4 = 1700 k, hpr = 42000 kj/kg, Cp = 1.004 kj/ kg.k
γ = 1.4
attached below is the detailed solution
