Answer:
74.85 kPA
Explanation:
P2=P1V1/V2
You can check this by knowing that P and V at constant T has an inverse relationship. Hence, this is correct.
Answer:
The answer to your question is 6.2 %
Explanation:
Data
mass of glucose (solute) = 27 g
mass of solvent = 410 g
Formula
Percent by mass = mass of solute/mass of solution x 100
-Substitution
Percent by mass = 27/(410 + 27) x 100
- Simplification
Percent by mass = 27/437 x 100
-Result
Percent by mass = 6.18 ≈ 6.2 %
Oxidation is when a substance gains oxygen molecules. For example when hydrogen reacts with oxygen it forms H₂O. The H₂ has been oxidised.
Answer:
A. The equilibrium constant for the reaction will stay the same.
B. The concentration of HB⁺(aq) will increase.
Explanation:
For the equilibrium:
B(aq) + H₂O(l) ⇌ HB(aq) + OH⁻(aq)
The equilibrium constant is:
K = [HB] [OH⁻] / [B]
A. The increase of B concentration will produce HB and OH⁻ in order to maintain <em>the equilibrium constant for the reaction constant.</em>
B. By LeChatelier's principle. An increase in the concentration of a reactant will result in predictable and opposing changes in the system that are the production of more HB(aq) and OH⁻(aq). Thus, <em>the concentration of HB⁺(aq) will increase.</em>
I hope it helps!