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kirill115 [55]
3 years ago
7

Add to the significant place: 20.1 + 2.00100 +48.28 + 0.015

Physics
1 answer:
chubhunter [2.5K]3 years ago
6 0

Answer:

Explanation:

20.1 + 2.00100 +48.28 + 0.015 = 70.396 ≈ 70.4

3 s.f.      6 s.f.       4 s.f.      3 s.f                     3 s.f

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A 75 kg Spider Man running at 3.0 m/s jumps onto a trash can lid that has a mass of 10kg and that is already moving in the same
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In order to find the final velocity of the skier and the trash can lid, we may apply the principle of conservation of momentum, which states that the total momentum of a system remains constant. Mathematically, in this case:
m₁v₁ + m₂v₂ = m₃v₃
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The final velocity is 2.88 m/s
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3 years ago
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You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You disc
FrozenT [24]

Answer:

The balloon hit the ground with velocity -15.34 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

You found that the best height to pitch a water balloon in order for it to

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We consider that the 12 meters is the maximum height, so the velocity

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To find the velocity when the balloon hits the ground lets use the rule

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the acceleration of gravity and h is the height.

u = 0 , h = 12 m , g = 9.8 m/s²

<em>Substitute these values in the equation above</em>

v² = 0 + 2(9.8)(12)

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v = ± \sqrt{235.2}

The velocity is downward, then it's a negative value

Then v = -15.34 m/s

<em>The balloon hit the ground with velocity -15.34 m/s</em>

6 0
3 years ago
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7) 6, i believe, (Cu) 1 atom+ (S) 1 atom+(0)4 atoms.
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3 years ago
if a car travels 30 miles north for one half hour, 50 miles east for one hour, and 30 miles south for 30 minutes, what is the to
egoroff_w [7]
50 miles east. because the 30 miles north then south cancel each other out. 
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4 years ago
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How fast should a moving clock travel if it is to be observed by a stationary observer as running at one-half its normal rate?A)
Elan Coil [88]

Answer:

Option (D) is correct.

Explanation:

Let the speed is v.

\Delta t = \gamma \Delta t'\\\\\Delta t = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\times \frac{\Delta t}{2}\\\\\sqrt{1-\frac{v^2}{c^2}} =\frac{1}{2}\\\\1-\frac{v^2}{c^2}=\frac{1}{4}\\\\\frac{3}{4}c^2 = v^2\\\\v = 0.87 c

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