Answer:

Explanation:
The angular momentum of the pulsar is given by:

where
is the mass of the pulsar
is the radius
is the angular speed
Given the period of the pulsar,
, the angular speed is given by

And so, the angular momentum is

So based on your question where there is a block of mass m1= 8.8kg in the inclined plane with an angle of 41 with respect to the horizontal. To find the spring constant of the problem were their is a coefficients of friction of 0.39 and 0.429, you must use the formula K*x^2=m*a*sin(angle). By calculating the minimum spring constant is 220.66 N/m^2