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PilotLPTM [1.2K]

2 years ago

14

Explain how static energy is generated?

2 answers:

antiseptic1488 [7]2 years ago

6 0

Answer:

Static energy is generated due to friction between two surfaces.

When two surfaces are rubbed, the surface with low work function will lose electrons to a surface with high work function. When the magnitude of positive charges are equal to magnitude of electrons. The field created between, generates static energy.

Explanation:

$.$

HACTEHA [7]2 years ago

3 0

$Question$

explain how static energy is generated?

Answer:

Hi, there! ♚♛♕♔ッ✨♚

Static electricity is the result of an imbalance between negative and positive charges in an object.

These charges can build up on the surface of an object until they find a way to be released or discharged

Hope this helps!!

♚♛♕♔ッ✨♚

-xXxAnimexXx-

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Calculate the enthalpy of the reaction below (∆Hrxn, in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g).

nalin [4]

The enthalpy change of the reaction below (ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

The bond energies data is given as follows:

BE for C≡O = 1072 kJ/mol

BE for Cl-Cl = 242 kJ/mol

BE for C-Cl = 328 kJ/mol

BE for C=O = 766 kJ/mol

The enthalpy change for the reaction is given as :

ΔHr×n = ∑H reactant bond - ∑H product bond

ΔHr×n = ( BE C≡O + BE Cl-Cl) - ( BE C=O + BE 2 × Cl-Cl )

ΔHr×n = ( 1072 + 242 ) - ( 766 + 656 )

ΔHr×n = 1314 - 1422

ΔHr×n = - 108 kJ

Thus, The enthalpy change of the reaction below ( ΔHr×n , in kJ) using the bond energies provided. CO(g) + Cl₂(g) → Cl₂CO(g). is - 108kJ.

To learn more about enthalpy here

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The combination of potassium-sparing diuretics and salt substitutes can result in dangerously high blood levels of:

alisha [4.7K]

Answer:

b. potassium.

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Concomitant use of potassium-sparing diuretics together with salt substitutes may result in dangerously high blood levels of serum potassium. For this reason, it is important to consult a physician before taking these substances at the same time to avoid potential problems with potassium accumulation.

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