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Answer:
2.8351×10^7 N/kg
Explanation:
We know that,
W = mg -------(1)
where W = weight, m = mass, g = gravitational acceleration
Also from Newton's law of gravitation we know that,
F = GMm/r²
Where,
F = gravitational force,
G = universal gravitational constant
M,m = masses of object under gravitational influence
r = distance between the two center of masses.
Here we get
F = (Gm/r²)M -------(2)
From 1 and 2
The acceleration due to gravity = gravitational field intensity
So if you consider the gravitational field intensity at the surface of the asteroid,it is equal to the acceleration due to gravity at the same place.
So we get,
g = (6.67×10^-11)×9.3835×10^20/(47²) = 2.8351×10^7 N/kg
Answer:
Option C. 4 Hz
Explanation:
To know the correct answer to the question given above, it is important we know the definition of frequency.
Frequency can simply be defined as the number of complete oscillations or circles made in one second.
Considering the diagram given above, the wave passes through the medium over a period of one second.
Thus, we can obtain the frequency by simply counting the numbers of complete circles made during the period.
From the diagram given above,
The number of circles = 4
Thus,
The frequency is 4 Hz
Answer:
The maximum frequency of revolution is 3.6 Hz.
Explanation:
Given that,
Mass = 8 kg
Distance = 400 mm
Tension = 800 N
We need to calculate the velocity
Using centripetal force

Where, F= tension
m = mass
v= velocity
r = radius of circle
Put the value into the formula



We need to calculate the maximum frequency of revolution
Using formula of frequency

Put the value into the formula


Hence, The maximum frequency of revolution is 3.6 Hz.
As velocities are tangent, the value of both Particle A and Particle B would be same for that point O (Intersecting point)
a = v / t
Here, v = 7, t = 6
So, a = 7/6
a = 1.17
As the graph is decreasing, value of acceleration would be negative.
So, a = -1.17 m/s²
In short, Your Answer would be Option C
Hope this helps!