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kotegsom [21]
2 years ago
13

What is the mode of heat transfer in case of greenhouse explain?​

Physics
1 answer:
Ugo [173]2 years ago
8 0

Answer:

Convection heat transfer is the physical movement of a warm gas or liquid to a colder location.

Explanation:

hope it helped

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Convert 5.7 miles to km
gayaneshka [121]

5.7 kilometers is equal to 3.5418157957528034 miles

4 0
3 years ago
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The gravitational force of a star on an orbiting planet 1 is F1. Planet 2, which is twice as massive as planet 1 and orbits at t
Andrej [43]

Answer:

ratio = 1 : 4.5

Explanation:

If m₁ is the mass of the star and m₂ the mass of the planet, the force of gravity F₁ for planet 1 is given by:

F_1=\frac{Gm_1m_2}{r^2}

The force F₂:

F_2=\frac{Gm_1(2m_2)}{(3r)^2}

The ratio:

\frac{F_2}{F_1}=\frac{2}{9}

8 0
3 years ago
A skier halfway between the top and bottom of a hill. Which statement best describes the skier?
Dvinal [7]

Answer: The skier has potential and kinetic energy.

Explanation: This is what I found from a different user on this website

5 0
3 years ago
Can someone answer this for me? it’s due today and i need it done asap! i will give brainlist!!
Setler79 [48]

Answer:

1. The sound waves are longitudinal because particles of the medium through which the sound is transported vibrate parallel to the direction that the sound wave moves.

2. A pulse or a wave is introduced into a slinky when a person holds the first coil and gives it a back-and-forth motion. This creates a disturbance within the medium; this disturbance subsequently travels from coil to coil, transporting energy as it moves.  

Explanation:

5 0
2 years ago
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The FM radio band in most places goes from frequencies of about 89 MHz to 106 MHz. How long is the wavelength of the radiation a
ohaa [14]

Answer:

2.83 m

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is given by

\lambda=\frac{c}{f}

where

\lambda is the wavelength

c=3.0\cdot 10^8 m/s is the speed of light

f is the frequency

For the FM radio waves in this problem, we have:

f_1=89 MHz=89\cdot 10^6 Hz is the minimum frequency, so the maximum wavelength is

\lambda_2=\frac{c}{f_1}=\frac{3\cdot 10^8}{89\cdot 10^6}=3.37 m

The maximum frequency is instead

f_2=106 MHz=106\cdot 10^6 Hz

Therefore, the minimum wavelength is

\lambda_1=\frac{c}{f_2}=\frac{3\cdot 10^8}{106\cdot 10^6}=2.83 m

So, the wavelength at the beginning of the range is 2.83 m.

8 0
2 years ago
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