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2 years ago

this part of the proposal begins with a capsule statement and than proceeds to introduce the subject to a stranger

Engineering

1 answer:

sesenic [268]2 years ago

4 0

Answer:

Introduction (including Statement of Problem, Purpose of Research, and Significance of Research): The introduction of a proposal begins with a capsule statement and then proceeds to introduce the subject to a stranger. ... This section is the heart of the proposal and is the primary concern of the technical reviewers.

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Explain what the ancient Romans did to solve the problem in the following scenario.

Nonamiya [84]

Answer:

They moved fresh water around their vast empire with aqueducts and canals.

Explanation:

6 0

2 years ago

(a) The lower yield point for an iron that has an average grain diameter of 1 x 10-2 mm is 230 MPa. At a grain diameter of 6 x 1

olya-2409 [2.1K]

Answer:

The answer is " $4.35 \times 10^{-3}\ mm$ and 157.5 MPa".

Explanation:

In point A:

The strength of its products with both the grain dimension is linked to this problem. This formula also for grain diameter of 310 MPA is represented as its low yield point

$y = yo + \frac{k}{\sqrt{x}}$

Here y is MPa is low yield point, x is mm grain size, and k becomes proportionality constant.

Replacing the equation for each condition:

$y = y_o + \frac{k}{\sqrt{(1 \times 10^{-2})}}\\\\\ \ \ \ \ \ \ 230 = yo + 10k\\\\ y = yo + \frac{k}{\sqrt{(6\times 10^{-3})}}\\\\275 = yo + 12.90k$

People can get yo = 275 MPa with both equations and k= 15.5 Mpa $mm^{\frac{1}{2}}$ .

To substitute the answer,

$310 = 275 + \frac{(15.5)}{\sqrt{x}}\\\\x = 0.00435 \ mm = 4.35 \times 10^{-3}\ mm$

In point b:

The equation is $\sigma y = \sigma 0 + k y d^{\frac{1}{2}}$

equation is:

$75 = \sigma o+4 ky \\\\175 = \sigma o+12 ky\\\\ky = 12.5 MPa (mm)^{\frac{1}{2}} \\\\ \sigma 0 = 25 MPa\\\\d= 8.9 \times 10^{-3}\\\\d^{- \frac{1}{2}} =10.6 mm^{-\frac{1}{2}}\\$

by putting the above value in the formula we get the $\sigma y$ value that is= 157.5 MPa

5 0

2 years ago

1. An air standard cycle is executed within a closed piston-cylinder system and consists of three processes as follows:1-2 = con

QveST [7]

Answer:

Explanation: Here it is: 67 Hope that helps! :)

5 0

2 years ago

The mechanical energy of an object is a combination of its potential energy and its

saveliy_v [14]

The mechanical energy of an object is a combination of its potential energy and its kinetic energy.

6 0

1 year ago

A drilling operation is performed on a steel part using a 12.7 mm diameter twist drill with a point angle of 118 degrees. The ho

Masteriza [31]

Answer:

a. Rotational speed of the drill = 375.96 rev/min

b. Feed rate = 75 mm/min

c. Approach allowance = 3.815 mm

d. Cutting time = 0.67 minutes

e. Metal removal rate after the drill bit reaches full diameter. = 9525 mm³/min

Explanation:

Here we have

a. N = v/(πD) = 15/(0.0127·π) = 375.96 rev/min

b. Feed rate = fr = Nf = 375.96 × 0.2 = 75 mm/min

c. Approach allowance = tan 118/2 = (12.7/2)/tan 118/2 = 3.815 mm

d. Approach allowance T∞ =L/fr = 50/75 = 0.67 minutes

e. R = 0.25πD²fr = 9525 mm³/min.

7 0

2 years ago