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vesna_86 [32]
2 years ago
6

The search for black holes involves searching for The search for black holes involves searching for Group of answer choices sing

le stars that emit large amounts of X-rays. a stellar core greater than 3 solar masses large spherical regions from which no light is detected. pulsars with periods less than one millisecond. pulsars that are orbited by planets.
Physics
1 answer:
trasher [3.6K]2 years ago
4 0

Answer:

Large spherical regions from which no light is detected

Explanation:

A black hole is an object that has an extremely high density such that it possesses very powerful gravitational force that prevents the escape of all objects including light from it, and consumes nearby objects.

Due to the power of the gravitational force of a black hole, at the center, objects are infinitesimally compressed resulting in the inapplicability of the concept of space and time and the location is known as a singularity

Therefore, the search for black holes involves searching for <em>large spherical regions from which no light is detected</em>.

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Define pressure snd state its SI units to​
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Answer:

Pressure (P) is the amount of force applied perpendicular to the surface of an object per unit area. The SI unit of pressure is the pascal (Pa), which is equivalent to N/m^{2} (newtons per meter squared).

6 0
3 years ago
Megan is waiting for the school bus. She sees it driving down the street straight toward her position. If the bus is moving at a
Maksim231197 [3]

Answer:

Explanation:

Is megan like going to be ran over the question doesn't have enoght info

4 0
3 years ago
Read 2 more answers
A spring hangs from the ceiling with an unstretched length of x 0 = 0.35 m . A m 1 = 6.3 kg block is hung from the spring, causi
Jlenok [28]

Answer:

x₂=0.44m

Explanation:

First, we calculate the length the spring is stretch when the first block is hung from it:

\Delta x_1=0.50m-0.35m=0.15m

Now, since the stretched spring is in equilibrium, we have that the spring restoring force must be equal to the weight of the block:

k\Delta x_1=m_1g

Solving for the spring constant k, we get:

k=\frac{m_1g}{\Delta x_1}\\\\k=\frac{(6.3kg)(9.8m/s^{2})}{0.15m}=410\frac{N}{m}

Next, we use the same relationship, but for the second block, to find the value of the stretched length:

k\Delta x_2=m_2g\\\\\Delta x_2=\frac{m_2g}{k}\\\\\implies \Delta x_2=\frac{(3.7kg)(9.8m/s^{2})}{410N/m}=0.088m

Finally, we sum this to the unstretched length to obtain the length of the spring:

x_2=0.35m+0.088m=0.44m

In words, the length of the spring when the second block is hung from it, is 0.44m.

3 0
3 years ago
A 125g steel ball with a kinetic energy of .25j rolls along a horizontal track how high up an inclined track will the ball roll
Sauron [17]
E = 0.25 = m*g*h 
<span>h = 0.25/(m*g) = 0.25/(0.125*10) = 0.25/1.25 = 1/5 = 0.20 m
I hope this helps you have a great day and im sorry it took so long to get an answer</span>
6 0
3 years ago
HELP!! TWO QUESTIONS FAST AND BRAINLIEST
IRINA_888 [86]

Answer:

1. The standard metric unit of momentum is the kg•m/s.

2. the units of momentum will be the product of the units of mass and velocity. Mass is measured in kg and velocity in ms-1, therefore, the SI unit of momentum will be kgm/s(-1).

3.Recall that acceleration is rate of change of velocity, so we can rewrite the Second Law: force = mass x rate of change of velocity. Now, the momentum is mv, mass x velocity. ... rate of change of momentum = mass x rate of change of velocity.

Explanation:

i really hope i helped sorry for the paragraphs ;( !

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