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3 years ago

Look at the image shown.

Chemistry

1 answer:

Charra [1.4K]3 years ago

6 0

Where’s the image sorry this isn’t much help but I don’t know what to answer if I can’t see the image

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What is the balanced chemical equation for the reaction of aqueous sodium hydroxide and sulfuric acid?

Andrews [41]

Answer:

H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O).

Explanation:

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3 years ago

You have a cold and symptoms include a runny nose, fever and coughing. How is your body working together to get rid of the bacte

topjm [15]

Your white blood cells are fighting the pathogen (sickness)

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4 years ago

Read 2 more answers

The reaction 3 BrO- (aq) --> BrO3- (aq) + 2 Br - (aq) in basic solution is second order in BrO-(aq) with a rate cons

Phoenix [80]

Answer:

0.124 M

Explanation:

The reaction obeys second-order kinetics:

$r = k[BrO^-]^2$

According to the integrated second-order rate law, we may rewrite the rate law in terms of:

$\dfrac{1}{[BrO^-]_t} = kt + \dfrac{1}{[BrO^-]_o}$

Here:

$k$ is a rate constant,

$[BrO^-]_t$ is the molarity of the reactant at time t,

$[BrO^-]_o$ is the initial molarity of the reactant.

Converting the time into seconds (since the rate constant has seconds in its units), we obtain:

$t = 1.00 min = 60.0 s$

Rearranging the integrated equation for the amount at time t:

$[BrO^-]_t = \dfrac{1}{kt + \dfrac{1}{[BrO^-]_o}}$

We may now substitute the data:

$[BrO^-]_t = \dfrac{1}{0.056 M^{-1}s^{-1}\cdot 60.0 s + \dfrac{1}{0.212 M}} = 0.124 M$

7 0

4 years ago

1.When a driver touches a car's steering wheel on a hot day, heart is transferred to the driver's hands by____.

marin [14]

I think the answer is
B,c,b,d,d,

5 0

3 years ago

Read 2 more answers

calculate the mass of 120cc nitrogen present at STP. how many number of molecules are present in it?

Stells [14]

Answer:

$0.15008\ \text{g}$

$3.23\times 10^{21}$

Explanation:

1 mol of nitrogen at STP = 22.4 L = 22400 cc

n = Mol of $N_2$ = $\dfrac{120}{22400}=0.00536\ \text{mol}$

M = Molar mass of $N_2$ = $28\ \text{g/mol}$

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

Mass of $N_2$ is

$m=nM\\\Rightarrow m=0.00536\times 28\\\Rightarrow m=0.15008\ \text{g}$

Mass of the nitrogen is $0.15008\ \text{g}$

Number of molecules is given by

$nN_A=0.00536\times 6.022\times 10^{23}=3.23\times 10^{21}\ \text{molecules}$

The number of molecules present in it are $3.23\times 10^{21}$

5 0

3 years ago