The amount of heat that is required to melt 22g piece of ice at -8 degrees to water at 14 degrees is 1,011.56 Joules.
<h3>How do we calculate the required heat?</h3>
Required amount of heat will be calculated by using the below equation as:
Q = mcΔT, where
m = mass = 22g
c = specific heat of ice = 2.09 J/g. degree C
ΔT = change in temperature = 14 - (-8) = 22 degree C
On putting all values, we get
Q = (22)(2.09)(22) = 1,011.56 J
Hence required amount of heat is 1,011.56 J.
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2 Na + 2 H2O → 2 NaOH + H2 (balanced equation)
The answer would be 2, since 2 in the coefficient of both Na and NaOH
since the concentration of Carbon Dioxide will increase, it would make Q > K, cause equilibrium to shift in the direction with less moles of gas to alleviate the extra pressure. In this case, the reaction will shift left because there are fewer moles of gas present.
Answer:
2 atoms of aluminium makes a molecule of aluminium
