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valentina_108 [34]
3 years ago
12

Consider the following two values for measurements of length:

Physics
1 answer:
xeze [42]3 years ago
5 0

We have that

a)  L1 = 0.0035600 km  = We have this number has 5 significant figures

    L2 = 136500 mm =We have this number has 3 significant figures

b) L1 = 0.0035600 km=3.65m

   L2 = 136500 mm=136.5m

c)  L1 is more accurate

d) L2 is more Precise

From the question we are told

Consider the following two values for measurements of length:

L1 = 0.0035600 km

L2 = 136500 mm

a)

Generally

L1 = 0.0035600 km  = We have this number has 5 significant figures

L2 = 136500 mm =We have this number has 3 significant figures

b)

Express each number in proper scientific notation after converting the units to “meters”

L1 = 0.0035600 km=3.65m

L2 = 136500 mm=136.5m

c)

Which of the two is more accurate

Generally

We define accuracy in measurement as the closes of a value measured to the actual value of

Therefore

L_1 is more accurate

d)

We define Precision in measurement as how closely the reoccurring results are close

Therefore

L_2 is more Precise

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Answer:

Explanation:

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For equilibrium

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F R sin( θ+δ )  = . 36 mg

F = .36 mg / Rsin( θ+δ )

For minimum F , sin( θ+δ ) should be maximum

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3 years ago
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k0ka [10]

Answer:

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7 0
2 years ago
This questic concerns a tablet that
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Answer:

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Explanation:

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where k is the decay rate (in our case 0.06/year), and t is the elapsed time in years. Therefore, after 2 years since manufacture we have:

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13. An object with a mass of 2.0 kg has a force of 4.0 newtons applied to it.
julsineya [31]

Answer:2m/s²

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Goshia [24]

Answer:

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Explanation:

Hope this helps :))

8 0
3 years ago
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