Answer:
a) 0.0875A
b) 2.06*10^-6m/s
Explanation:
given
Diameter, d = 2.6mm = 0.0026m
Charge, Q = 420C
Time, t = 80mins = 80*60s = 4800s
Concentration of electrons, n = 5*10^28
To find the current, recall that q = it
Therefore, i = Q/t
Current, i = 420/4800
i = 0.0875A
To get the drift velocity, recall that I = n*q*Vd*A
A = πd²/4
A = π*0.0026²/4
A = 5.3*10^-6m²
Then, Vd = I/nqA
Vd = 0.0875/(5*10^28 * 1.6*10^-19 * 5.3*10^-6)
Vd = 0.0875/42400
Vd = 2.06*10^-6m/s
Note, low Vd causes low current.
Therefore, the current is 0.0875A and the Vd is 2.06*10^-6m/s
The wavelength of a wave of frequency 4 Hz and speed 2 m/s is 0.5 m.
Answer:
Explanation:
As we know that speed of a wave is directly proportional to the product of wavelength and frequency of the wave. If any two variables are known, then we can easily find the third parameter.
Like, in this case, the wavelength is not given, instead the frequency is given as 4 Hz and speed is given as 2 m/s, so the wavelength can be easily determined.
Speed = Wavelength × Frequency
Then Wavelength = speed/frequency
So, wavelength = 2/4=0.5 m
Thus, the wavelength of a wave of frequency 4 Hz and speed 2 m/s is 0.5 m.
I would say the most beautiful
A. Two objects coming in contact with each other
Answer:
(a) = 3910
(b) = 5181
(c) = 2762955 m
Explanation:
Using equations of uniformly accelerated motion:
Equations:
-
-
(a) Using equation 1:
⇒ Because it upward from rest
(b) Using equation 1:
⇒ Because is the is the initial speed in the movement before changing acceleration
(c) Using equation 2:
⇒ and Because it upward from rest
⇒