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3 years ago

The Blue Giant of the Orient is the largest faceted sapphire in the world, with a mass of

Chemistry

1 answer:

vfiekz [6]3 years ago

5 0

The volume of this sapphire in cubic centimeters is 24.4 cm^3

We have the following information;

Mass of the Blue Giant = 486.52 carats

Density of the blue giant = 3.98 g/cm3

Volume of the blue giant = ?

Since the density is given in g/cm3, we must convert the mass to grams.

We have the conversion factor; 5 carats = 1 g

So;

If 5 carats make 1g

486.52 carats make 486.52 carats × 1g/ 5 carats

= 97.30 g

Since;

Density = mass/volume

Volume = Mass/Density

Volume = 97.30 g/3.98 g/cm3

Volume = 24.4 cm^3

Learn more: brainly.com/question/6034174

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Which of the following is a compound? a. iron b. lead c. helium d. methane

Lana71 [14]

The correct answer is d) methane ( $CH_4$ )

The other options are elements.

6 0

2 years ago

A reaction produces 74.10 g Ca(OH)2 after 56.08 g CaO is added to 36.04 g H2O. How should the difference in the masses of reacta

melomori [17]

Cao + H2O ---->Ca(OH)2
Calculate the number of each reactant and the moles of the product
that is
moles = mass/molar mass
The moles of CaO= 56.08g/ 56.08g/mol(molar mass of Cao)= 1mole
the moles of water= 36.04 g/18 g/mol= 2.002moles
The moles of Ca (OH)2=74.10g/74.093g/mol= 1mole

The mass of differences of reactant and product can be therefore
explained as
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3 0

3 years ago

Determine the number of grams of Carbon in 215 g of sucrose.

olya-2409 [2.1K]

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6 0

3 years ago

At 100 degrees Celsius, the ion product for pure water is Kw= 51.3*10^-14. What is the pOH of water at this temperature? A) 7.00

Levart [38]

7.86 is the pOH of water at this temperature of 100 degrees celsius.

Option E is the right answer.

Explanation:

Data given:

Kw = 51.3 x $10^{-14}$

pOH = ?

we know that pure water is neutral and will have pH pf 7.

The equation for relation between Kw and H+ and OH- ion is given by:

Kw = [H+] [OH-}

here the concentration of H+ ion and OH- ion is equal

so, [H+]= [OH-]

Putting the values in the equation of Kw

pKw = -log[Kw]

pKw = -log [51.3 x $10^{-14}$ ]

pKw = 12.28

since H+ ion OH ion concentration is equal the pH of water is half i.e. 6.14

Now, pOH is calculated by using the equation:

14 = pOH + pH

14- 6.14 = pOH

pOH = 7.86

8 0

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natima [27]

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3 years ago