Question

A person pushes two boxes with a horizontal force F of magnitude of 100 N.

Answer 1

The magnitude of the action–reaction pair between the two boxes (A and B) will be "18.2 N".

According to the question,

Mass of box A,

• $m_A = 9\ kg$

Mass of box B,

• $m_B = 2 \ kg$

Horizontal force,

• $F_{app} = 100 \ N$

From the Newton's law,

→ $F_{app} = (\frac{F_{app}}{m_A+m_B} )a$

or,

→      $a = \frac{F_{app}}{(m_A+m_B)}$

Bu substituting the values, we get

→         $= \frac{100}{9+2}$

→         $= \frac{100}{11}$

→         $9.10 \ m/s^2$

We can see that between the two boxes, the action-reaction pair exist.

then,

→ $F_{action-reaction} = m_b \ a$

→                          $=2\times 9.10$

→                          $= 18.2 \ N$ (magnitude)

Thus the above solution is appropriate.

 

Learn more about the magnitude here:

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