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HACTEHA [7]
2 years ago
10

Naturally occurring gallium consists of two isotopes. One of those isotopes is 71Ga with an isotopic mass of 70.9247050 amu and

an abundance of 39.892% . What is the mass number of the other isotope?
Chemistry
1 answer:
charle [14.2K]2 years ago
3 0

The mass of the other isotope is 68.9254620 amu.

Let the first isotope (⁷¹Ga) be A

Let the other isotope be B

Let the mass of the other isotope be y

From the question given above, the following data were obtained:

<h3>For A (isotope ⁷¹Ga):</h3>

Mass of A = 70.9247050 amu

Abundance (A%) = 39.892%

<h3>For B (the other isotope): </h3>

Abundance (B%) = 100 – 39.892

Abundance (B%) = 60.108%

<h3>Mass of B = y =? </h3><h3 /><h3>Recall:</h3>

Atomic mass of gallium = 69.723

The mass of the other isotope can be obtained as illustrated below:

<h3>Atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100] </h3>

69.723 = [(70.9247050 × 39.892)/100] + [(y × 60.108)/100]

69.723 = 28.2932833 + 0.60108y

Collect like terms

69.723 – 28.2932833 = 0.60108y

41.4297167 = 0.60108y

Divide both side by 0.60108

y = 41.4297167 / 0.60108

<h3>y = 68.9254620 amu</h3>

Therefore, the mass of the other isotope is 68.9254620 amu

Learn more: brainly.com/question/5063053

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Answer:

The concentration of NaCl = 0.3374 M

Explanation:

Given :

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Volume of AgNO₃ = 20.22 mL

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1 mL= 10^{-3} L

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Molarity of a solution is the number of moles of solute present in 1 L of the solution.

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

The formula can be written for the calculation of moles as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

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Moles\ of\ AgNO_3 =Molarity \times {Volume\ of\ the\ solution}

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The chemical reaction taking place:

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According to reaction stoichiometry:

<u>1 mole</u> of AgNO₃ reacts with <u>1 mole</u> of NaCl

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5.0611×10⁻³ moles of AgNO₃ reacts with 5.0611×10⁻³ moles of NaCl

Thus, moles of NaCl required = 5.0611×10⁻³ moles

Volume of NaCl required = 15.00 mL

The conversion of mL into L is shown below:

1 mL= 10^{-3} L

Thus, volume of the solution = 15.00×10⁻³ L

Applying in the formula of molarity as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity\ of\ NaCl=\frac{5.0611\times 10^{-3}}{15.00\times 10^{-3}}

Molarity\ of\ NaCl= 0.3374 M

<u>Thus, the concentration of NaCl = 0.3374 M</u>

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