What effect does the force from your foot have on the Earth?

What two systems work with the digestive system to control digestion speed?

kobusy [5.1K]

The nervous system and the circulatory system

7 0

4 years ago

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A mango fruit drops from the top of it's tree which is 40 m. How long does it takes to reach the ground

IrinaVladis [17]

T=distance over speed
T=40m over 9.8ms
T=answer

4 0

3 years ago

What will be the answer??

AnnZ [28]

5-a). Acceleration is a vector defined as the rate of change of velocity.
Its magnitude has units of [length/time²]. The SI unit is meter/second².
Its direction is the direction in which velocity is increasing.

5-b). The graph says that the object's speed is not changing.
When we look at any time, from zero to almost 50 minutes, the
object's speed is the same . . . 60 m/s . This will make it easy.

There are 60 seconds in a minute, so 30 minutes = 1,800 seconds.
In every one of those seconds, the object covered 60 meters.
It travelled a total of (60 m/s)·(1,800 s) = 108,000 meters (108 km) .

8 0

4 years ago

A. Draw the electric field lines around a negative charge.

Alborosie

<h2>a. Answer:</h2>

We use Electric field lines for visualizing electric fields, so this helps us to see the problem more real. So an electric field line is an imaginary line or curve drawn through a region of space such that the tangent at any point comes from the direction of the electric-field vector at that point. The electric field lines around a negative charge is shown in the First figure below.

<h2>b. Answer:</h2>

Electric forces can be found by using the Coulomb Law's that states <em>that The magnitude of the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. </em>This can be expressed as follows:

$F=k\frac{\left | q_{1}q_{2} \right |}{r^2} \\ \\ Where: \\ \\ k=9\times 10^9Nm^2/c^2 \\ \\ q_{1}=0.00150 C \ and \ q_{2}=0.00240 C \\ \\ r=0.900 m$

Then:

$F=9\times 10^9\frac{\left | 0.00150 \times 0.00240 \right |}{(0.900)^2} \\ \\ \therefore \boxed{F=40000N}$

This force is repulsive because the two charges are positive and recall that two positive charges or two negative charges repel each other while a positive charge and a negative charge attract each other.

<h2>C. Answer:</h2>

From the statement, we have two charged objects. Let's say that this charges are:

$q_{1} \ and \ q_{2}$

If the amount of charge on one of the objects is tripled, let's say this is the charge $q_{2}$ , then the new charge is:

$q_{N}=3q_{2}$

In the formula of Coulomb:

$F=k\frac{\left | q_{1}q_{N} \right |}{r^2} \\ \\ \therefore F=k\frac{\left | q_{1}(3q_{2}) \right |}{r^2} \\ \\ \therefore \boxed{F=3k\frac{\left | q_{1}q_{2} \right |}{r^2}}$

<em>The conclusion is that if the amount of charge on one of the objects is tripled, the electric force between two charged objects is also tripled</em>

<h2>d. Answer:</h2>

Let's use the Coulomb's Law again to solve this problem. We want to know how the electric force between two charged objects changes if the charges are moved closer together:

$F=k\frac{\left | q_{1}q_{N} \right |}{r^2}$

<em>By saying that the charges are moved closer together, we want to express that r becomes smaller. Since r is in the denominator, this implies that the electric force between these two charged objects becomes greater.</em>

<h2>e. Answer:</h2>

From the figure, we can see a metal sphere on a stand. There we have both positive and negative charges. We can say that the positive charge of this sphere is +10q and the negative and the negative charge is -10q. Since the electric charge is conserved, then the algebraic sum of all the electric charges in any closed system is constant. In conclusion, <em>the sphere has no net charge.</em>

<h2>f. Answer:</h2>

Here we want to know how the negative charges in the same sphere are redistributed when a positively charged rod is brought near it. Therefore, positive charge on rod repels positive charges on the sphere, creating zones of negative and positive charge as indicated in the second Figure.

7 0

3 years ago

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What is the critical angle and how does it relate to total internal reflection?

liubo4ka [24]

Answer:

critical angle is the angle of incidence in optically denser medium, for which the angle of reflection in the less denser medium is 90 degree

Explanation:

total internal reflection occurs at one particular angle of incidence where the reflected ray lies on the boundary.

this angle is called the critical angle

6 0

3 years ago