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Anvisha [2.4K]
3 years ago
11

What effect does the force from your foot have on the Earth?

Physics
1 answer:
Alex73 [517]3 years ago
3 0
Gravitional force
It depends on your mass
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According to Coulomb’s Law, the force between two charged objects is related to _____.
Natasha_Volkova [10]

Answer:

A.) the inverse of the square of the distance separating them

Explanation:

Coulombs law states that "the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them."

Mathematically, F = kq1q2/r²

Where q1 and q2 are the charges

r is the distance between the charges.

According to the law, the force between two charged objects is related to the inverse of the square of the distance separating them.

5 0
4 years ago
Which remains the same as the distance of an object from Earth changes?
Gemiola [76]

Answer:

MASS

Explanation:

weight has to do with the gravitational pull, as distance from earth decreases, so does the gravitational pull. meaning, the size of the force, the pull, and the weight would all change. mass stays the same (in this sense. if you gain weight on earth you will gain mass as well, but if you leave earth your weight will lessen and your mass will stay the same.)

hope this helped.

5 0
4 years ago
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On Earth, the number flux of solar neutrinos from the p-p chain is:
Nataly [62]

Answer:

Explanation:

The volume of the tank = 50 kton

50 kton = 5 × 10⁷ kg

Since 18 grams of water will contain: 10 electrons × 6.023 × 10²³

Then;

5× 10⁷ kg will contain ( \dfrac{5 \times 10^7 \times 10^3}{18}) \times 10 \times 6.023 \times 10^{23}

= 1.67 × 10³⁴ electrons

(b)

Suppose:

f_{neutrino} = \dfrac{2f_o}{26.2 MeV} = 6.7\times 10^{10} \ s^{-1} cm^{-2}

Then;

10⁻⁶ of f_{neutrino} = 6.7 \times 10^{10} \times 10^{-6} \ s^{-1} cm^{-2}

=6.7 \times 10^{4}\ s^{-1} cm^{-2}

Thus, the number of high energy neutrinos which will interact with water is:

= 6.7 \times 10^4 \times \sigma

= 6.7 \times 10^4  \times 10^{-43}

= 6.7 \times 10^{-39} s^{-1}

For  1.67 × 10³⁴ electrons, the detection rate is:

6.7 \times 10^{-39}  \times 1.67 \times 10^{34}

= 11.19 \times 10^{-5} \ s^{-1}

= 9.668 per day

3 0
3 years ago
When an atom is neutral the...?
KATRIN_1 [288]

Answer:

c

Explanation:

if numbers of protons and electrons are equal, the atom is neutral

5 0
3 years ago
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Question 6 of 15
Vera_Pavlovna [14]

Answer: sliding

Explanation:

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4 years ago
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