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3 years ago

What element is found in liver and is needed to prevent anemia or tired blood.

Chemistry

1 answer:

DochEvi [55]3 years ago

3 0

The element found in the liver that helps prevent anemia is iron.

Iron is an essential element for blood production. Close to 70% of the body's iron is found in the red blood cells. In the red blood cells it is a vital ingredient of hemoglobin, the red pigment that gives blood its red color. In the muscle cells, iron is found as myoglobin.

Iron is stored mostly in the liver as ferritin or hemosiderin.

When iron stores are finished or exhausted, the condition is called iron depletion. When the shortage of iron is severe, it results in a condition known as iron deficiency anemia whereby the red blood cells do not have enough hemoglobin.

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CH 4 History and Structure of the Atom

Butoxors [25]

Answer:

a) Cl, 17 protons and 17 electrons

Explanation:

The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. The atomic number of chlorine is 17. Its means it has 17 protons and 17 electrons.

The sum of neutrons and protons is the mass number of an atom while the number of protons are number of electrons is the atomic number of an atom. Thus the atomic mass of chlorine will be 17+18 = 35 amu

Number protons = 17

Number of electrons = 17

Number of neutrons = 18

Properties of Chlorine:

1. it is greenish-yellow irritating gas.

2. its melting point is 172.2 K

3. its boiling point is 238.6 K

4. it is disinfectant and can kill the bacteria.

5. it is also used in manufacturing of paper, paints and textile industries.

5 0

3 years ago

You titrate 25.00 mL of the lemon-lime Kool-Aid (with KI, HCl, and starch) with 0.001000 M KIO3(aq) solution. The titration requ

Svetradugi [14.3K]

Answer:

1.0190 x 10⁻⁵ mol

Explanation:

We know the titration required 10.19 mL of 0.001000 M KIO₃, from this information we can calculate the number of moles KIO₃ reacted and from there the number of moles of ascorbic acid since it is a monoprotic acid ( 1 equivalent of ascorbic acid to one equivalent KIO₃).

Molarity = mol/V

V KIO₃ = 10.19 mL = 10.19 mL x 1 L/1000 mL = 0.01019 L

⇒ mol KIO₃ = V x M = 0.01019 L x 0.0010 mol / L = 1.0190 x 10⁻⁵ mol KIO₃

# mol ascorbic acid = # mol KIO₃ = 1.0190 x 10⁻⁵ mol

8 0

2 years ago

HELP PRETTY PLEASE QUICKLY!!! AND ILL GIVE YOU BRAINLIEST

Yuri [45]

Answer: The answer is C

Explanation: Sound waves tend to spread farther the deeper the sound is, and the waves go lower then the second example, deeming it is louder.

8 0

3 years ago

A farmer selectively breeds tomatoes to be shipped to grocery stores across the United States. Which of the following genetic tr

Studentka2010 [4]

Answer:

Explanation:

It would definitely affect size because breeding will change that trait

5 0

2 years ago

En un experimento hacemos reaccionar 12 g de carbono con 32 g de oxígeno para formar dióxido de carbono. Razona si podemos saber

max2010maxim [7]

Answer:

La masa de óxido de carbono iv formado es 44 g.

Explanation:

En esta pregunta, se nos pide calcular la masa de óxido de carbono iv formado a partir de la reacción de masas dadas de carbono y oxígeno.

En primer lugar, necesitamos escribir una ecuación química equilibrada.

C + O2 → CO2

De la ecuación, 1 mol de carbono reaccionó con 1 mol de oxígeno para dar 1 mol de óxido de carbono iv.

Ahora, si marca las masas en la pregunta, verá que corresponde a la masa atómica y la masa molar de la molécula de carbono y oxígeno, respectivamente. ¿Qué indica esto?

Como tenemos una relación molar de 1: 1 en todo momento, lo que esto significa es que la masa de óxido de carbono iv producida también es la misma que la masa molar de óxido de carbono iv.

Por lo tanto, procedemos a calcular la masa molar de óxido de carbono iv Esto es igual a 12 + 2 (16) = 12 + 32 = 44 g Por lo tanto, la masa de óxido de carbono iv formado es 44 g

5 0

3 years ago