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3 years ago

What element is found in liver and is needed to prevent anemia or tired blood.

Chemistry

1 answer:

DochEvi [55]3 years ago

3 0

The element found in the liver that helps prevent anemia is iron.

Iron is an essential element for blood production. Close to 70% of the body's iron is found in the red blood cells. In the red blood cells it is a vital ingredient of hemoglobin, the red pigment that gives blood its red color. In the muscle cells, iron is found as myoglobin.

Iron is stored mostly in the liver as ferritin or hemosiderin.

When iron stores are finished or exhausted, the condition is called iron depletion. When the shortage of iron is severe, it results in a condition known as iron deficiency anemia whereby the red blood cells do not have enough hemoglobin.

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15.630 g milk chocolate bar ks found to contain 9.815g of sugar. how many milligrams of sugar does the bar contain?

sleet_krkn [62]

Well there are 1,000 milligrams in 1 gram so 9.815 grams of sugar is equivalent to 9,815 milligrams of sugar. So a bar of milk chocolate contains 9,815 milligrams of sugar.

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3 years ago

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A reaction of 41.9 g of Na and 30.3 g of Br2 yields 36.4 g of NaBr . What is the percent yield?

Licemer1 [7]

Answer: The percent yield is, 93.4%

Explanation:

First we have to calculate the moles of Na.

$\text{Moles of Na}=\frac{\text{Mass of Na}}{\text{Molar mass of Na}}=\frac{41.9g}{23g/mole}=1.82moles$

Now we have to calculate the moles of $Br_2$

${\text{Moles of}Br_2} = \frac{\text{Mass of }Br_2 }{\text{Molar mass of} Br_2} =\frac{30.3g}{160g/mole}=0.189moles$

${\text{Moles of } NaBr} = \frac{\text{Mass of } NaBr }{\text{Molar mass of } NaBr} =\frac{36.4g}{103g/mole}=0.353moles$

The balanced chemical reaction is,

$2Na(s)+Br_2(g)\rightarrow 2NaBr$

As, 1 mole of bromine react with = 2 moles of Sodium

So, 0.189 moles of bromine react with = $\frac{2}{1}\times 0.189=0.378$ moles of Sodium

Thus bromine is the limiting reagent as it limits the formation of product and Na is the excess reagent.

As, 1 mole of bromine give = 2 moles of Sodium bromide

So, 0.189 moles of bromine give = $\frac{2}{1}\times 0.189=0.378$ moles of Sodium bromide

Now we have to calculate the percent yield of reaction

$\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100=\frac{0.353 mol}{0.378}\times 100=93.4\%$

Therefore, the percent yield is, 93.4%

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3 years ago

Silver is a white metal that is an excellent conductor. Silver tarnishes when exposed to air and light. The density of silver is

Stells [14]

Answer:

c tarnishes in air

Explanation:

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Verdich [7]

You would find the highest pressure at the bottom

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jeyben [28]

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