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Alexandra [31]
3 years ago
14

Within the nucleus, where does ribosome assembly occur?

Chemistry
1 answer:
Ymorist [56]3 years ago
3 0
<span>It occurs like most protein synthesis, in the cytoplasm just outside the nucleus.</span>
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What is the molarity of H3PO4?
masya89 [10]
The answer is 14.8 hoped this helped
3 0
3 years ago
Drag and drop the labels provided into the boxes below to explain how the Earth-Sun-Moon system results in these seasons on Eart
GalinKa [24]
In order: tilted, rotates, revolving.
6 0
3 years ago
If you burn 29.4 g of hydrogen and produce 263 g of water, how much oxygen reacted?
vovikov84 [41]

The reaction between hydrogen and oxygen to form water is given as:

H_2 + O_2 \rightarrow H_2O

The balanced reaction is:

2H_2 + O_2 \rightarrow 2H_2O

According to the balanced reaction,

4 g of hydrogen (4\times 1) reacts with 32 g of oxygen (2\times 16).

So, oxygen reacted with 29.4 g of hydrogen is:

\frac{29.4\times 32}{4} = 235.2 g

Hence, the mass of oxygen that is reacted with 29.4 g of hydrogen is 235.2 g.

7 0
3 years ago
Calculate the adjusted retention times for both pentafluorobenzene and benzene if the elution time for unretained solute is 1.06
vovangra [49]

Answer:

Pentafluorobenzene: 11,92 min

Benzene: 12,14 min

Explanation:

<em>Retention time of pentafluorobenzene is 12,98 min and 13,20 min of benzene.</em>

The adjusted retention time is the time an analyte spends in the column not the stationary phase. As time of unretained solute is 1,06 min the adjusted retention time for an analyte is:

tr' = tr - 1,06min

For pentafluorobenzene:

tr' = 12,98min - 1,06min = <em>11,92 min</em>

For benzene:

tr' = 13,20 - 1,06min = <em>12,14 min</em>

<em></em>

I hope it helps!

3 0
3 years ago
An antacid tablet with an active ingredient of CaCO3 was dissolved in 50.0 mL of 0.300 M HCl. When this solution was titrated wi
yaroslaw [1]

Answer:

Explanation:

mole of HCl remaining after reaction with CaCO₃

= .3 M of NaOH of 32.47 mL

= .3 x .03247 moles

= .009741 moles

Initial HCl taken = .3 x .005 moles = .0015 moles

Moles of HCl reacted with CaCO₃

= .009741 - .0015 = .008241 moles

CaCO₃     +    2HCl   =   CaCl₂  +  CO₂  +  H₂O .

1 mole        2 moles

2 moles of HCl reacts with 1 mole of  CaCO₃

.008241 moles of HCl reacts with .5 x .008241 moles of  CaCO₃

CaCO₃ reacted with HCl =  .5 x .008241 = .00412 moles

the mass (in grams) of calcium carbonate in the tablet

= .00412 x 100 = .412 grams . ( molar mass of calcium carbonate = 100 )

5 0
3 years ago
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