Answer:
The SI unit of force is Newton.
Explanation:
Newton is denoted by N.
Force can be defined as the pull or push which change or try to change the state of a body from motion to rest or rest to motion in a straight line.
Answer:
F = 614913.88 N
Explanation:
We are given;
Mass of pile driver; m = 1800 kg
Height of fall of pole driver; h = 4.6 m
Depth driven into beam; d = 13.6 cm = 0.136 m
Now, from energy equations and applying to this question, we can write that;
Workdone = Change in potential energy
Formula for workdone is; W = F × d
While the average potential energy here is; W = mg(h + d)
Thus;
Fd = mg(h + d)
Where F is the average force exerted by the beam on the pile driver while in bringing it to rest.
Making F the subject, we have;
F = mg(h + d)/d
F = 1800 × 9.81 × (4.6 + 0.136)/0.136
F = 614913.88 N
<span>Ans : Bernoulli's principle states for incompressible non-viscous flow that
p/Ď + gâ™h + (1/2)â™v² = constant
Evaluate the equation along a stream line from liquid surface of the reservoir (1) to the inlet of the pipe
pâ‚/Ď + gâ™hâ‚ + (1/2)â™v₲ = pâ‚‚/Ď + gâ™hâ‚‚ + (1/2)â™v₂²
=>
vâ‚‚ = âš[ 2â™(pâ‚-pâ‚‚)/Ď + 2â™gâ™(hâ‚-hâ‚‚) + v₲ ]
lets make some assumptions:
- the pressure at the liquid surface is equal to the atmospheric pressure
pâ‚ = 1atm = 101325Pa
- the velocity of the liquid at the surface (that is the speed at which the liquid level in reservoir decreases) is quite small, so it may be ignored:
v₠≠0
So
vâ‚‚ = âš[ 2â™(pâ‚-pâ‚‚)/Ď + 2â™gâ™(hâ‚-hâ‚‚) ]
The height difference is fixed. So the only variable remaining is the pressure in the pipe. As higher it is as lower the velocity in the pipe is.
So you get the maximum velocity for the minimum pressure.
Since pressure cannot drop below zero this is
pâ‚‚ = 0
Therefore
vâ‚‚max = âš[ pâ‚/Ď + gâ™(hâ‚-hâ‚‚) ]
= âš[ 2â™101325Pa/1000kg/mÂł + 2â™9.81m/s²â™12m ]
= 20.93m/s</span>
