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PolarNik [594]
3 years ago
13

What happens if a acid hits aluminum​

Chemistry
2 answers:
satela [25.4K]3 years ago
7 0

Answer:

Acids that form a complex with aluminum ions can eat their way through the oxide coating, however, so concentrated hydrochloric acid can dissolve aluminum. Zinc is also very reactive and lacks the passivating layer found on aluminum, so it reduces hydrogen ions from acids like hydrochloric acid to form hydrogen gas.

Marta_Voda [28]3 years ago
3 0

Answer:

Acids that form a complex with aluminum ions can eat their way through the oxide coating, however, so concentrated hydrochloric acid can dissolve aluminum. Zinc is also very reactive and lacks the passivating layer found on aluminum, so it reduces hydrogen ions from acids like hydrochloric acid to form hydrogen gas.

Explanation:

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Anna71 [15]

Answer:

This flexible ability is important because it allows the cell to survive in differing environments, such as when immersed in water over long periods of time.

4 0
2 years ago
The process of splitting and Atom into two lighters atoms is called?
natima [27]
<span>The process of splitting and Atom into two lighters atoms is called </span>Nuclear Fission
5 0
3 years ago
In the reaction fecl2 + 2naoh fe(oh)2(s) + 2nacl, if 6 moles of fecl2 are added to 6 moles of naoh, how many moles of fecl2 woul
pychu [463]
The balanced chemical reaction would be 

<span>fecl2 + 2naoh =  fe(oh)2(s) + 2nacl

Initial amounts of the reactants are given, so, we need to determine which of the reactants is the limiting reactant and use this amount to determine what is asked. However, what is being asked is how many of the FeCl2 is used in the reaction, showing that it is NaOH that is the limiting reactants. Thus, we just use the initial amount of NaOH and relate the substances by the chemical reaction as follows:

6 mol NaOH ( 1 mol FeCl2 / 2 mol NaOH ) = 3 mol FeCl2

Therefore, 3 moles of FeCl2 is used up and 3 moles of FeCl2 is also left after the reaction.</span>
5 0
3 years ago
Read 2 more answers
Why don't siblings look exactly alike
marusya05 [52]

Answer:

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3 0
3 years ago
In step 2, of the experiment, the procedure uses 3.0M NaOH. However, the student notices that the only solution of NaOH is conce
Luda [366]

Answer:

We need 78.9 mL of the 19.0 M NaOH solution

Explanation:

Step 1: Data given

Molarity of the original NaOH solution = 19.0 M

Molarity of the NaOH solution we want to prepare = 3.0 M

Volume of the NaOH solution we want to prepare = 500 mL = 0.500 L

Step 2: Calculate volume of the 19.0 M NaOH solution needed

C1*V1 = C2*V2

⇒with C1 = the concentration of the original NaOH solution = 19.0 M

⇒with V1 = the volume of the original NaOH solution = TO BE DETERMINED

⇒with C2 = the concentration of the NaOH solution we want to prepare = 3.0 M

⇒with V2 = the volume  of the NaOH solution we want to prepare = 500 mL = 0.500 L

19.0 M * V2 = 3.0 M * 0.500 L

V2 = (3.0 M * 0.500L) / 19.0 M

V2 = 0.0789 L

We need 0.0789 L

This is 0.0789 * 10^3 mL = 78.9 mL

We need 78.9 mL of the 19.0 M NaOH solution

8 0
3 years ago
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