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vichka [17]
3 years ago
12

Why don't we see objects in the universe colliding or moving towards each other due to gravitational force?​

Physics
2 answers:
Citrus2011 [14]3 years ago
8 0

Answer:

the objects in the universe are evenly placed. This means that a celestial object's gravity may not be able to attract another object. Another reason may be that the stars in solar systems act as points of equilibrium for the planets in the system. Take for example the sun. It maintains the position of the planets in the system and likewise the earth maintains the position of the moon. You can picture it as evenly placed atoms in matter and the subsequent electrons held by the nucleus

Natali5045456 [20]3 years ago
3 0

Answer:

BECAUSE OF THE DISTANCEBETWEEN EACH OBJECT DECREASES THE CHANCE IN SEEING OBJECTS COLIDE. HOPE THIS HELPS ...

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If a galaxy has an apparent radial velocity of 2000 km/s and the Hubble constant is 70 km/s/Mpc, how far away is the galaxy
ddd [48]

Answer:

28.57 Mpc

Explanation:

This question is going to be solved by applying Hubble's Law.

This Hubble's Law is actually an observation in physical cosmology. This observation makes it clear that galaxies are moving away from the Earth, and are doing so at speeds proportional to their distance. This essentially means that the farther they are from the Earth, the faster they are moving away from Earth.

It is represented by this formula

v = H(0)D, where

v = speed

H(0) = Constant of proportionality, or otherwise, Hubble's constant.

D = Distance to a galaxy

Applying the given parameters to the formula, we have

v = H(0).D

D = v / H(0)

D = 2000 / 70

D = 28.57 Mpc

3 0
3 years ago
Isoleucine, leucine, lysine, methionine, phenylalanine, threonine, tryptophan, and valine are known as the ____.
Sveta_85 [38]
The answer is amino acids :). hope that helped!
4 0
3 years ago
What does the force of gravity depend on?
Julli [10]
Force of Gravity depends on: 

1) Masses of the object
2) Distance between the object 

Hope this helps!
7 0
3 years ago
A block is at rest on the incline shown in the figure. The coefficients of static and ki- netic friction are μs = 0.62 and μk =
GREYUIT [131]

The frictional force is 218.6 N

Explanation:

The block in the problem is at rest along the inclined surface: this means that the net force acting along the direction parallel to the incline must be zero.

There are two forces acting along this direction:

- The component of the weight parallel to the incline, downward along the plane, of magnitude

mg sin \theta

where

m = 46 kg is the mass

g=9.8 m/s^2 is the acceleration of gravity

\theta=29^{\circ} is the angle of the incline

- The (static) frictional force, acting upward, of magnitude F_f

Since the block is in equilibrium, we can write

mg sin \theta - F_f = 0

And substituting, we find the force of friction:

F_f = mg sin \theta = (46)(9.8)(sin 29^{\circ})=218.6 N

Learn more about frictional force along an inclined plane:

brainly.com/question/5884009

#LearnwithBrainly

7 0
3 years ago
A ball is thrown at an angle of to the ground. If the ball lands 90 m away, what was the initial speed of the ball?
andre [41]

Answer:

The initial speed of the ball is 30 m/s.

Explanation:

It can be assumed that the ball is thrown at an angle of 45 degrees to the ground. The ball lands 90 m away. We need to find the initial speed of the ball. We know that the horizontal distance covered by the projectile is called its range. It is given by :

R=\dfrac{u^2\ sin2\theta}{g}

u is the initial speed of the ball.

v=\sqrt{\dfrac{Rg}{sin2\theta}}

v=\sqrt{\dfrac{90\times 9.8}{sin2(45)}}

v = 29.69 m/s

or

v = 30 m/s

So, the initial speed of the ball is 30 m/s. Hence, this is the required solution.                                      

8 0
3 years ago
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