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abruzzese [7]
3 years ago
14

Whats 1+1 = free pints to anyone that wants them//

Engineering
1 answer:
enot [183]3 years ago
3 0

Answer:

2

Explanation:

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The density of a certain type of steel is 8.1 g/cm3. What is the mass of a 100 cm3 chunk of this steel
irina1246 [14]

Answer:

  810 g

Explanation:

Mass is the product of density and volume:

  m = ρV

  m = (8.1 g/cm³)(100 cm³) = 810 g

The mass of the chunk is 810 grams.

4 0
2 years ago
A round bar of chromium steel, (ρ= 7833 kg/m, k =48.9 W/m-K, c =0.115 KJ/kg-K, α=3.91 ×10^-6 m^2/s) emerges from a heat treatmen
Lerok [7]

Answer:

Q = 424523.22 kw

Explanation:

\rho =7833 kg/m

k = 48.9 W/m - K

c = 0.115 KJ/kg- K

\alpha = 3.91*10^{-6} m^2/s

T_s = 285 degree celcius

T_∞ = 35 degree celcius

velocity of air stream = 15 m/s

D = 40 cm

L = 200 cm

mass flow rate\dot m = \rho AV = 7833 *\frac{\pi}{4} 0.4^2*15

\dot m = 14764.85 kg/s

A_s = \pi DL = \pi 0.4*2 = 2.513 m^2

Q = \dot m C \Delta T = h A_s \Delta T

\dot m C \Delta T = h A_s \Delta T

solving for h

h = \frac{14764.85*0.115*(285-35)}{2.513*(285-35)}

h = 675.6 kw/m^2K

Q = h A_s\Delta T

Q = 675.6*2.513*(285-35)

Q = 424523.22 kw

7 0
3 years ago
Okay bro let’s go man yes yes
r-ruslan [8.4K]
Sheeeeeesh bro same name ayoooo??
8 0
3 years ago
Read 2 more answers
Solar energy stored in large bodies of water, called solar ponds, is being used to generate electricity. If such a solar power p
fgiga [73]

Answer: 1.137*10^7 Btu/h.

Explanation:

Given data:

Efficiency of the plant = 4.5percent

Net power output of the plant = 150kw

Solution:

The required collection rate

QH = W/n

= 150/0.045 * 0.94782/ 1 /60 */60 Btu/h.

= 3333.333 *3412.152Btu/h.

= 11373840 Btu/h

= 1.137*10^7 Btu/h.

3 0
3 years ago
Are designed to make it easier for employees to get health and safety Information about
iren [92.7K]

Answer:

what the options

Explanation:

4 0
3 years ago
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