Answer:
5.en
6.ex
7.ex
8.en
Explanation:
<h3>#CARRY ON LEARNING</h3><h3>#BRAINLITS </h3>
Answer:
BC and DE
Explanation:
In the given figure, the velocity time graph is shown. We know that the area under v-t curve gives the displacement of the particle.
Area under AB, ![d_1=\dfrac{1}{2}\times 2\times 10=10\ m](https://tex.z-dn.net/?f=d_1%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%2010%3D10%5C%20m)
Area under BC, ![d_2=\dfrac{1}{2}\times 2\times 4=4\ m](https://tex.z-dn.net/?f=d_2%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%204%3D4%5C%20m)
Area under CD, ![d_3=\dfrac{1}{2}\times 2\times 7=7\ m](https://tex.z-dn.net/?f=d_3%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%207%3D7%5C%20m)
Area under DE, ![d_4=\dfrac{1}{2}\times 2\times 4=4\ m](https://tex.z-dn.net/?f=d_4%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%204%3D4%5C%20m)
Area under EF, ![d_5=\dfrac{1}{2}\times 2\times 3=3\ m](https://tex.z-dn.net/?f=d_5%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%202%5Ctimes%203%3D3%5C%20m)
So, form above calculations it is clear that, during BC and DE undergo equal displacement. Hence, the correct option is (c) "BC and DE = 4 meters".
F=nmv
where;
n=no. of bullets = 1
m=mass of bullets=2g *10^-3
V=velocity of bullets200m/sec
F=1
loss in Kinetic energy=gain in heat energy
1/2MV^2=MS∆t
let M council M
=1/2V^2=S∆t
M=2g
K.E=MV^2/2
=(2*10^-3)(200)^2/2
2 councils 2
2*10^-3*4*10/2
K.E=40Js
H=mv∆t
(40/4.2)
40Js=40/4.2=mc∆t
40/4.2=2*0.03*∆t
=158.73°C
Answer:
24m/s²
Explanation:
Given
Distance S = 3m
Time of fall = 0.5sec
Required
Acceleration due to gravity
Using the equation of motion
S = ut+1/2gt²
Substitute the given values
3 = 0+1/2g(0.5)²
3 = 1/2(0.25)g
3 = 0.125g
g = 3/0.125
g = 24
Hence the value for the acceleration of gravity on this new planet is 24m/s²
11.3 Electromagnetic spectrum (ESADK)
EM radiation is classified into types according to the frequency of the wave: these types include, in order of increasing frequency, radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays and gamma rays.