Answer:
Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.
Explanation:
We have been given that the average distance of Enceladus from Saturn is 238,000 km; the average distance of Titan from Saturn is 1,222,000 km.
We will use Kepler's Law to solve our given problem.
Upon substituting our given values, we will get:
Taking square root of both sides, we will get:
This implies that time period of Titan about Sturn is 11.634 times more compared to time period of Enceladus about Saturn.
So, basically Titan takes 11.634 times longer to orbit Saturn as compared to Enceladus.
Answer:
3.63 s
Explanation:
We can solve the problem by using the equivalent SUVAT equations for the angular motion.
To find the angular acceleration, we can use the following equation:
where
is the final angular speed
is the initial angular speed
is the angular distance covered
is the angular acceleration
Re-arranging the formula, we can find :
Now we want to know the time the bit takes starting from rest to reach a speed of . So, we can use the following equation:
where:
is the angular acceleration
is the final speed
is the initial speed
t is the time
Re-arranging the equation, we can find the time:
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B is the correct answer i guess
Part a)
Volume flow rate is given as
Part b)
Volume flow rate = area * speed
Part c)
for the speed of efflux we know that
d) we need figure to find this part