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snow_tiger [21]
3 years ago
13

What is the weighted average mass of chlorine

Physics
1 answer:
JulijaS [17]3 years ago
3 0

Answer:

35.48 amu

Explanation:

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A sled and rider with a combined mass of 70 kg are at the top of a hill that rises 9 m above the level ground below. The sled is
kvv77 [185]

Answer:

(A) 6174J, 0J.

(B) 7374J

(C) 7374J

Explanation:

See the attachment below for the calculation.

The princi6of conservation of energy has been used.

E = K1 + U1 = K2 + U2

Where E = total mechanical energy.

Taking the bottom as reference, and h =0 and as a result U2 = mg(0) = 0J.

The complete solution to the problem can be found in the attachment below.

3 0
3 years ago
An object exhibits SHM with an angular frequency w = 4.0 s-1 and is released from its maximum displacement of A = 0.50 m at t =
vivado [14]

Explanation:

It is given that,

Angular frequency, \omega=4\ s^{-1}

Maximum displacement, A = 0.5 m at t = 0 s

We need to find the time at which it reaches its maximum speed. Firstly, we will find the maximum velocity of the object that is exhibiting SHM.

v_{max}=A\times \omega

v_{max}=0.5\times 4

v_{max}=2\ m/s............(1)

Acceleration of the object, a=\omega^2A

a=4^2\times 0.5

a=8\ m/s^2...............(2)

Using first equation of motion we can calculate the time taken to reach maximum speed.

v=u+at

t=\dfrac{v-u}{a}

t=\dfrac{2-0}{8}

t = 0.25 s

So, the object will take 0.25 seconds to reach its maximum speed. Hence, this is the required solution.

4 0
3 years ago
Which of the following best defines amplitude?
ziro4ka [17]
The answer to that question is C
8 0
4 years ago
Y=1/2 at^2 solve for t
Aloiza [94]

Explanation:

y = ½ at²

Multiply both sides by 2:

2y = at²

Divide both sides by a:

t² = 2y/a

Take the square root of both sides:

t = √(2y/a)

6 0
3 years ago
A piano tuner is tuning a piano when he discovers that the G above middle C is vibrating with a higher frequency than his G tuni
kotegsom [21]

Answer:

Tuning a piano is the process of adjusting the tension of its strings, thereby altering their pitch, or frequency of vibration, by slightly turning the tuning pins to which they're attached, so that each string sounds pleasingly in harmony with every other string.

<h2>Hopefully u will satisfy with my answer of ur question..!!</h2>

<h2>Have a nice day ahead dear..!!</h2>
6 0
3 years ago
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