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Nana76 [90]
3 years ago
14

There are competitions in which pilots fly small planes low over the ground and drop weights, trying to hit a target. Part A A p

ilot flying low and slow drops a weight; it takes 3.4 s to hit the ground, during which it travels a horizontal distance of 120 m. Now the pilot does a run at the same height but twice the speed. How much time does it take the weight to hit the ground? Express your answer with the appropriate units. tt = nothing nothing
Physics
1 answer:
tamaranim1 [39]3 years ago
5 0

Explanation:

A pilot flying a weight; it takes t = 3.4 s to hit the ground, during which it travels a horizontal distance d = 120 m  

h = g/2*t^2

h= 4.903*3.4^2

h=56.701 m

V = d/t

V= 120/3.4

V=35.3 m/sec  

Now the pilot does a run at the same height but twice the speed.  

How much time (t1) does it take the weight to hit the ground?

t1 = t = 3.4 sec (depending just upon height)

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(a) 8 V, (b) 144000 V, (c) 2 x 10^(-8) C

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(b)

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Let the charge is q.

W= q V

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