Use the table below to answer the questions.
2 answers:
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Answer:
The electron will get at about 0.388 cm (about 4 mm) from the negative plate before stopping.
Explanation:
Recall that the Electric field is constant inside the parallel plates, and therefore the acceleration the electron feels is constant everywhere inside the parallel plates, so we can examine its motion using kinematics of a constantly accelerated particle. This constant acceleration is (based on Newton's 2nd Law:
and since the electric field E in between parallel plates separated a distance d and under a potential difference , is given by:
then :
We want to find when the particle reaches velocity zero via kinematics:
We replace this time (t) in the kinematic equation for the particle displacement:
Replacing the values with the information given, converting the distance d into meters (0.01 m), using , and the electron's kinetic energy:
we get:
Therefore, since the electron was initially at 0.5 cm (0.005 m) from the negative plate, the closest it gets to this plate is:
0.005 - 0.00112 m = 0.00388 m [or 0.388 cm]
Answer:
E = 4.75 x 10⁻¹⁶ J
Explanation:
given,
wavelength of the x-ray , λ = 4.18 Å
Energy of photon = ?
we know
where h is the planks constant
c is the speed of light
h = 6.626 x 10⁻³⁴ m² kg / s
c = 3 x 10⁸ m/s
now,
E = 4.75 x 10⁻¹⁶ J
hence, the energy of the photon is equal to E = 4.75 x 10⁻¹⁶ J