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trasher [3.6K]
3 years ago
13

Use the table below to answer the questions.

Physics
2 answers:
inessss [21]3 years ago
7 0
Student three because it says 2.71
Llana [10]3 years ago
6 0

Answer:

Don t know

Explanation:

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20 POINTS!!!
hram777 [196]
I think its inductance. If its not then I think its none of the above
5 0
3 years ago
India used 600 joules of work on a steel block and moved it 4.8 meters. How much forced was used ?
dangina [55]
The formula for finding force is F=W/d so then you plug in the numbers:
F=600/4.8
F=125N
8 0
3 years ago
An electron is trapped between two large parallel charged plates of a capacitive system. The plates are separated by a distance
Lorico [155]

Answer:

The electron will get at about 0.388 cm (about 4 mm) from the negative plate before stopping.

Explanation:

Recall that the Electric field is constant inside the parallel plates, and therefore the acceleration the electron feels is constant everywhere inside the parallel plates, so we can examine its motion using kinematics of a constantly accelerated particle. This constant acceleration is (based on Newton's 2nd Law:

F=m\,a\\q\,E=m\,a\\a=\frac{q\,E}{m}

and since the electric field E in between parallel plates separated a distance d and under a potential difference \Delta V, is given by:

E=\frac{\Delta\,V}{d}

then :

a=\frac{q\,\Delta V}{m\,d}

We want to find when the particle reaches velocity zero via kinematics:

v=v_0-a\,t\\0=v_0-a\,t\\t=v_0/a

We replace this time (t) in the kinematic equation for the particle displacement:

\Delta y=v_0\,(t)-\frac{1}{2} a\,t^2\\\Delta y=v_0\,(\frac{v_0}{a} )-\frac{a}{2} (\frac{v_0}{a} )^2\\\Delta y=\frac{1}{2} \frac{v_0^2}{a}

Replacing the values with the information given, converting the distance d into meters (0.01 m), using \Delta V=100\,V, and the electron's kinetic energy:

\frac{1}{2} \,m\,v_0^2= (11.2)\,\, 1.6\,\,10^{-19}\,\,J

we get:

\Delta\,y= \frac{1}{2} v_0^2\,\frac{m (0.01)}{q\,(100)} =11.2 (1.6\,\,10^{-19})\,\frac{0.01}{(1.6\,\,10^{-19})\,(100)}=\frac{11.2}{10000}  \,meters=0.00112\,\,metersTherefore, since the electron was initially at 0.5 cm (0.005 m) from the negative plate, the closest it gets to this plate is:

0.005 - 0.00112 m = 0.00388 m [or 0.388 cm]

8 0
4 years ago
An x-ray has a wavelength of 4.18 Å. Calculate the energy (in J) of one photon of this radiation. Enter your answer in scientifi
Damm [24]

Answer:

E = 4.75 x 10⁻¹⁶ J

Explanation:

given,

wavelength of the x-ray , λ = 4.18 Å

Energy of photon = ?

we know

E = \dfrac{hc}{\lambda}

where h is the planks constant

          c is the speed of light

h = 6.626 x 10⁻³⁴ m² kg / s

c = 3 x 10⁸ m/s

now,

E = \dfrac{6.626\times 10^{-34}\times 3 \times 10^8}{4.18\times 10^{-10}}

E = 4.75 x 10⁻¹⁶ J

hence, the energy of the photon is equal to E = 4.75 x 10⁻¹⁶ J

4 0
4 years ago
A diffraction grating is to be used to find the wavelength of the emission spectrum of a gas. The grating spacing is not known,
Bumek [7]

Answer:

528.9 nm

Explanation:

For a grating dsinθ = mλ where m = order of grating, d = grating space, λ = wavelength of light and θ = angle of deflection of light

First, we find the grating space d = mλ/sinθ where m = 2 for second order, λ = 632.8 nm = 632.8 × 10⁻⁹ m, θ = 43.2°

d = mλ/sinθ = 2 × 632.8 × 10⁻⁹ m ÷ sin43.2° = 1.849 × 10⁻⁶ m = 1.849 μm

We now find the wavelength of the light to be measured from λ = dsinθ/m

Here, θ = 34.9° and m = 2 for second order. So, we have

λ = dsinθ/m = 1.849 × 10⁻⁶ m × sin34.9° ÷ 2 = 0.5289 × 10⁻⁶ m = 528.9 nm

7 0
3 years ago
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