The precipitate formed when a solution of manganese(II) nitrate and
potassium sulfide react is Manganese sulfide (MnS)
To obtain the precipitate formed when a solution of manganese(II) nitrate and potassium sulfide react, we shall write the balanced ionic equation. This is illustrated below:
Manganese (II) nitrate => Mn(NO₃)₂
Potassium sulfide => K₂S
In solution, they will react as follow:
Mn(NO₃)₂ (aq) —> Mn²⁺(aq) + 2NO₃¯(aq)
K₂S(aq) —> 2K⁺(aq) + S²¯(aq)
Mn(NO₃)₂ (aq) + K₂S(aq) —>
Mn²⁺(aq) + 2NO₃¯(aq) + 2K⁺(aq) + S²¯(aq) —> MnS(s) + 2K⁺(aq) + 2NO₃¯(aq)
Cancel out the spectator ions (i.e K⁺ and NO₃¯)
Mn²⁺(aq) + S²¯(aq) —> MnS(s)
From the net ionic equation above, we can see that MnS is insoluble.
Therefore, the precipitate formed when a solution of manganese(II) nitrate and potassium sulfide react is Manganese sulfide (MnS)
Learn more: brainly.com/question/21280827
