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3 years ago

What is the formula for the precipitate when solutions of manganese (II) nitrate and

Chemistry

1 answer:

natita [175]3 years ago

6 0

The precipitate formed when a solution of manganese(II) nitrate and

potassium sulfide react is Manganese sulfide (MnS)

To obtain the precipitate formed when a solution of manganese(II) nitrate and potassium sulfide react, we shall write the balanced ionic equation. This is illustrated below:

Manganese (II) nitrate => Mn(NO₃)₂

Potassium sulfide => K₂S

In solution, they will react as follow:

Mn(NO₃)₂ (aq) —> Mn²⁺(aq) + 2NO₃¯(aq)

K₂S(aq) —> 2K⁺(aq) + S²¯(aq)

Mn(NO₃)₂ (aq) + K₂S(aq) —>

Mn²⁺(aq) + 2NO₃¯(aq) + 2K⁺(aq) + S²¯(aq) —> MnS(s) + 2K⁺(aq) + 2NO₃¯(aq)

Cancel out the spectator ions (i.e K⁺ and NO₃¯)

Mn²⁺(aq) + S²¯(aq) —> MnS(s)

From the net ionic equation above, we can see that MnS is insoluble.

Therefore, the precipitate formed when a solution of manganese(II) nitrate and potassium sulfide react is Manganese sulfide (MnS)

Learn more: brainly.com/question/21280827

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3 years ago

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3 years ago

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