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Ulleksa [173]
3 years ago
11

A 1,500 kg Audi race car travels at 30 m/s. a). What is its momentum? b) If the same car slows to a stop, what is its final mome

ntum? c). What is the change in momentum of the car from 30 m/s to stop. d) If the car slows down in 5 seconds, what force does the car experience in braking?
Physics
1 answer:
Sedbober [7]3 years ago
7 0

The momentum, final momentum, change in momentum and force experience by a 1500 kg racing car travelling at 30 m/s are:

A. The momentum of the car is 45000 Kgm/s

B. The final momentum of the car is 0 Kgm/s

C. The change in the momentum of the car is –45000 Kgm/s

D. The force experienced by the car is –9000 N

Momentum is simply defined as the product of mass and velocity i.e

<h3>Momentum = mass × velocity </h3>

A. Determination of the momentum of the car.

Mass = 1500 Kg

Velocity = 30 m/s

<h3>Momentum =? </h3>

Momentum = mass × velocity

Momentum = 1500 × 30

<h3>Momentum = 45000 Kgm/s</h3>

Thus, the momentum of the car is 45000 Kgm/s

B. Determination of the final momentum of the car

Mass = 1500 Kg

Final Velocity = 0 m/s

<h3>Final Momentum =?</h3>

Final momentum = mass × Final velocity

Final momentum = 1500 × 0

<h3>Final momentum = 0 Kgm/s</h3>

Thus, the final momentum of the car is 0 Kgm/s.

C. Determination of the change in the momentum of the car

Initial momentum = 45000 Kgm/s

Final momentum = 0 Kgm/s

<h3>Change in momentum =?</h3>

Change in momentum = Final momentum – Initial momentum

Change in momentum = 0 – 45000

<h3>Change in momentum = –45000 Kgm/s</h3>

Thus, the change in the momentum of the car is –45000 Kgm/s

D. Determination of the force experienced by the car.

Change in momentum = –45000 Kgm/s

Time = 5 s

<h3>Force =? </h3>

Force = change in momentum / time

Force = –45000 / 5

<h3>Force = –9000 N</h3>

Thus, the force experienced by the car is –9000 N

Learn more: brainly.com/question/250648

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