It becomes a different element
Answer:
(a)
(b)
(c)
Explanation:
(a) According to Newton's second law, the acceleration of a body is directly proportional to the force exerted on it and inversely proportional to it's mass.
(b) According to Newton's third law, the force that the sled exerts on the girl is equal in magnitude but opposite in the direction of the force that the girl exerts on the sled:
(c) Using the kinematics equation:
For the girl, we have and . So:
For the sled, we have . So:
When they meet, the final positions are the same. So, equaling (1) and (2) and solving for t:
Now, we solve (1) for
To solve this exercise it is necessary to apply the concepts related to Centripetal and Perimeter acceleration of a circle.
The perimeter of a circle is defined by
Where,
r= radius
While centripetal acceleration is defined by
Where,
v= velocity
r= radius
PART A)
The distance of a body can be defined based on the speed and the time traveled, that is
x = v*t
For our values the distance is equal to
x = 15*115=1725m
The plane when going to make the turn from east to south makes a quarter of the circumference that is
The same route you take is the distance traveled, that is
PART B)
With the radius is possible calculate he centripetal acceleration,
Therefore the radius of the curva that the plane follows in making the turn is 1098.17m with a centripetal acceleration of
Basketball is played with two<span> teams, with </span>4 players<span> from each team on the court at one time. The maximum number of players on the bench differs by league. In international play, a maximum of </span>7 players<span> are allowed on the bench, resulting in a roster of </span>12 players<span>.
I hope this helps!
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Answer:
the smallest separation between two objects is 0.8067 m
Explanation:
Given the data in the question;
Altitude h = 5.75 km = 5750 m
Diameter D = 4.0 mm = 0.004 m
λ = 460 nm = 4.6 × 10⁻⁷ m
Now, Using Rayleigh criterion for Airy disks resolution.
we know that, Minimum angular separation for resolving two points is;
θ = 1.22λ / D
so we substitute
θ = (1.22 × 4.6 × 10⁻⁷) / 0.004
θ = 5.612 × 10⁻⁷ / 0.004
θ = 1.403 × 10⁻⁴ rad
so minimum separation = θh
so we substitute
= (1.403 × 10⁻⁴) × 5750 m
= 0.8067 m
Therefore, the smallest separation between two objects is 0.8067 m