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a_sh-v [17]
3 years ago
11

Just as a skydiver steps out of the helicopter with no forward velocity someone who’s watching start stopwatch so the time is ze

ro as a skydiver steps out of the plane what is the sky divers downward velocity at that entrance just before starting to fall
Physics
1 answer:
Kobotan [32]3 years ago
6 0

Answer: zero.


Justification:


The downward velocity of the sky diver just before starting to fall is zero, assuming that the helicopter is not moving but just hovering.


Before starting to fall, the velocity of the skydiver is the same of the helicopter, which is zero. It is only, once she jumps out of the helicopter that her weight is not supported by the helicopter and so the gravitational force of the Earth attracts the skydiver and she starts to gain velocity at a rate equal to g (around 9.81 m/s²).

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A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber
Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}

Now calculate the bouyant force acting on the lead

F_L = Vpg

F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N

This force will act in upward direction

Gravitational force on the lead due to its mass  will act in downward direction

Hence the difference of this two force

T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N

If V is the volume submerged in the water then bouyant force on the bobber is

F_B=V'pg

Equate bouyant force with the tension and gravitational force

F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}

Now Total volume of bobble is

\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\

=\large\boxed{4.52 \%}

7 0
3 years ago
Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia
Gala2k [10]

Answer:

Una secadora de cabello tiene una resistencia de 10Ω al circular una corriente de 6 Amperes, si está conectado a una diferencia de potencial de 120 V, durante 18 minutos ¿Qué cantidad de calor produce?, expresado en calorías

5 0
3 years ago
The Earth's crust is made of tectonic plates. These plates are constantly in motion. How are earthquakes related to the movement
never [62]

Answer:

I'm pretty sure it's B because I studied this topic and I'm not right I'm sorry.

5 0
2 years ago
Read 2 more answers
A light bulb operating at a voltage of 120 v has a resistance of 200 ω. what is the power?
cluponka [151]

The correct is 72 watt

We know that formula of power is P=\frac{v^{2} }{r}

so putting the value of Voltage and Resistance in Formula of power so we get

P=\frac{120^{2} }{200} =72

What is Power?

Electric power is the rate at which an electric circuit transfers electrical energy per unit time.

Typically, electricity is generated by generators, but it can also be supplied by sources such as electric batteries. The electric power industry typically distributes it via an electric power grid to businesses and homes (as domestic mains electricity).

Transmission lines allow electric power to be delivered over long distances and used for high-efficiency applications such as motion, light, or heat.  Electric charges are converted to other forms of energy when they pass through an electric potential difference (voltage).

To learn more about Power from the given link:

brainly.com/question/2333114

#SPJ4

4 0
1 year ago
A magnetic field is perpendicular to the plane of a single-turn circular coil. The magnitude of the field is changing, so that a
Reika [66]

Answer:

2.62A

Explanation:

Given

V = 0.43 V

I = 3.1 A

Then, V = IR, R = V/I

R = 0.43/3.1

R = 0.14 Ω

The induced emf = dB/dt * A

So that, dB/dt = emf/A

Since dB/dt is constant then Emf/A(circle) = Emf/A square

So Emf (square)/Emf (circle) = A square / A circle

A circle = πr². The perimeter of the square is 2πr which also is the circumference of the square.

Since the perimeter is 2πr, then each side would be πr/2. Thus, the area of the square would be, (πr/2)² = π²r²/4

So A square/Acircle = (π²r²/4) / πr² = π/4 = 0.79

this means that, emf square = emf circle * 0.79

emf square = 0.43*0.79 = 0.34V

I = V/R

I = 0.34/0.13

I = 2.62A

3 0
3 years ago
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