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a_sh-v [17]
3 years ago
11

Just as a skydiver steps out of the helicopter with no forward velocity someone who’s watching start stopwatch so the time is ze

ro as a skydiver steps out of the plane what is the sky divers downward velocity at that entrance just before starting to fall
Physics
1 answer:
Kobotan [32]3 years ago
6 0

Answer: zero.


Justification:


The downward velocity of the sky diver just before starting to fall is zero, assuming that the helicopter is not moving but just hovering.


Before starting to fall, the velocity of the skydiver is the same of the helicopter, which is zero. It is only, once she jumps out of the helicopter that her weight is not supported by the helicopter and so the gravitational force of the Earth attracts the skydiver and she starts to gain velocity at a rate equal to g (around 9.81 m/s²).

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Answer:

Uranium

Explanation:

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4 years ago
An object weighs 60.0 kg on the surface of the earth. How much does it weigh 4R from the surface? (5R from the center)
Alecsey [184]
"60 kg" is not a weight.  It's a mass, and it's always the same
no matter where the object goes.

The weight of the object is   

                                 (mass) x (gravity in the place where the object is) .

On the surface of the Earth,

                   Weight = (60 kg) x (9.8 m/s²)

                                =      588 Newtons.

Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to  5R  from the center, the gravity out there is

                    (1R/5R)²  =  (1/5)²  =  1/25  =  0.04 of its value on the surface.

The object's weight would also be 0.04 of its weight on the surface.

                 (0.04) x (588 Newtons)  =  23.52 Newtons.

Again, the object's mass is still 60 kg out there.
___________________________________________

If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink. 
You are being planted with sloppy, inaccurate, misleading
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6 0
3 years ago
A 6.50-g sample of copper metal at 25.0°C is heated by the addition of 84.0 J of energy. The final temperature of the copper is
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Answer:

Final temperature of the copper is 59 degrees Celsius

Explanation:

It is given that,

Mass of the sample of copper metal, m = 6.5 g

Initial temperature of the metal, T_i=25^{\circ}\ C=298\ K

Heat generated, Q = 84 J

The specific heat capacity of liquid water is 0.38 J/g-K

Let T_f is the final temperature of the copper. It can be calculated using the definition of specific heat of any substance. It is given by :

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Q=mc(T_f-T_i)

T_f=\dfrac{Q}{mc}+T_i

T_f=\dfrac{84}{6.5\times 0.38}+298

T_f=332\ K

or

T_f=59^{\circ}C

So, the final temperature of the copper is 59 degrees Celsius. Hence, this is the required solution.

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