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statuscvo [17]
3 years ago
6

What is the Orbital Notation for Radon

Physics
1 answer:
balu736 [363]3 years ago
4 0

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

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A lamp uses a 230 V mains supply and transfers 96 J of energy every second. Work out the current through the lamp. Give your ans
sertanlavr [38]

Answer:

0.4 A

Explanation:

From the question,

Electric power = Voltage×current

P = VI.......................... Equation 1

Make I the subject of the equation

I = P/V..................... Equation 2

Given: P = 96 J/s, V = 230 V.

Substitute into equation 2

I = 96/230

I = 0.4 A.

Hence the current is 0.4 A

8 0
4 years ago
What happens when you sit in a chair?
stellarik [79]
B Yea that should be the right answer
3 0
3 years ago
1) A change in momentum is the result of an
dimaraw [331]

Answer: Either a change in mass or velocity or both.

Explanation: Since the equation for momentum is p (momentum) = m (mass)* v (velocity), if the mass or velocity (or both) of the object is changed, the momentum will change.

8 0
4 years ago
Please explain how to solve 17 and 18
andriy [413]

Answer:

17. h = l − l cos θ

18. 1.40 m

Explanation:

Let's call d the height of the triangle.  We can then say:

h = l − d

Using trig, we can write d in terms of l and θ:

d = l cos θ

h = l − l cos θ

If l = 6 m and l cos θ = 40°:

h = 6 − 6 cos 40

h ≈ 1.40

3 0
3 years ago
A high-jumper, having just cleared the bar, lands on an air mattress and comes to rest. Had she landed directly on the hard grou
Hoochie [10]

Answer:

e. the air mattress exerts the same impulse, but a smaller net avg force, on the high-jumper than hard-ground.

Explanation:

This is according to the Newton's second law and energy conservation that the force exerted by the hard-ground is more than the force exerted by the mattress.

The hard ground stops the moving mass by its sudden reaction in the opposite direction of impact force whereas the mattress takes a longer time to stop the motion of same mass in a longer time leading to lesser average reaction force.

<u>Mathematical expression for the Newton's second law of motion is given as:</u>

F=\frac{dp}{dt} ............................................(1)

where:

dp = change in momentum

dt = time taken to change the momentum

We know, momentum:

p=m.v

Now, equation (1) becomes:

F=\frac{d(m.v)}{dt}

<em>∵mass is constant at speeds v << c (speed of light)</em>

\therefore F=m.\frac{dv}{dt}

and, \frac{dv}{dt} =a

where: a = acceleration

\Rightarrow F=m.a

also

F\propto \frac{1}{dt}

so, more the time, lesser the force.

<em>& </em><u><em>Impulse:</em></u>

I=F.dt

I=m.a.dt

I=m.\frac{dv}{dt}.dt

I=m.dv=dp

∵Initial velocity and final velocity(=0), of a certain mass is same irrespective of the stopping method.

So, the impulse in both the cases will be same.

4 0
3 years ago
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