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Aleks [24]
2 years ago
5

What is "plant food"?

Chemistry
1 answer:
frosja888 [35]2 years ago
7 0

Answer:

Plant food is the sugars created via photosynthesis. The sugar created is glucose which can be used by the plant for energy and also to make other things like starch and cellulose.

Explanation:

Plant food is the sugars created via photosynthesis. The sugar created is glucose which can be used by the plant for energy and also to make other things like starch and cellulose. I hope this helps : )

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For water to change from a liquid to solid, thermal energy needs to be <br><br> .
telo118 [61]

answer: dispersed from the liquid so cold air can take its place

6 0
2 years ago
1.6x10^23 lead atoms. Find the weight in grams
Ber [7]
Moles of lead(Pb) = 1.6x10^23/6.02x10^23 = 0.265 moles.

Weight of lead = moles x atomic weight of lead
                         =  0.265x207.2
                         =  54.908 grams.

Hope this helps!
5 0
3 years ago
Write a net ionic equation to show that hydroiodic acid, hi, behaves as an acid in water.
OlgaM077 [116]

Answer:

HI(aq) + H₂O(ℓ) ⟶ H₃O⁺(aq) + I⁻(aq)

Explanation:

The HI donates a proton to the water, converting it to a hydronium ion

HI(aq) + H₂O(ℓ) ⟶ H₃O⁺(aq) + I⁻(aq)

Thus, the HI is behaving like a Brønsted acid.

3 0
3 years ago
Read 2 more answers
What mass of calcium carbonate (in grams) can be dissolved by 4.0 g of hcl? (hint: begin by writing a balanced equation for the
stiks02 [169]
The reaction between calcium carbonate and hydrochloric acid can be expressed through the chemical reaction,

    CaCO3 + 2HCl --> CaCl2 + H2O + CO2

The molecular weight of calcium carbonate is 100 g/mol while that of hydrochloric acid is 36.45. The equation above depicts that 100 g of calcium carbonate can be dissolved in 72.9 g of hydrochloric acid. 

    x = (4 g HCl)(100 g CaCO3 / 72.9 HCl)
      x = 5.49 g

Answer: 5.49 g
8 0
3 years ago
Read 2 more answers
What are 2 metric system units for measuring liquid volume?
Step2247 [10]

Answer:

milliliters and liters.

3 0
3 years ago
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