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ivann1987 [24]
3 years ago
11

Kích thước của nguyên tử gần nhất với

Chemistry
1 answer:
trapecia [35]3 years ago
4 0

Answer:

The size of the atom closest to 30 to 300 pm

Explanation:

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Which of the following statements is true?
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D) during chemical reactions the number and types of atoms
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Which formula represents a hydrocarbon?<br><br><br> CaO2<br><br> C5H12<br><br> CH2O<br><br> H2SO4
Stella [2.4K]
A hydrocarbon has only hydrogen and carbon in it. the 1st, 3rd and 4th option all include Oxygen so the only hydrocarbon is option 2
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3 years ago
PLEASE HELP CHEM BABES I HAVE BEEN CRYING FOR A WHILE NOW
slavikrds [6]

Answer: See below

Explanation:

1. To calculate the mass, you know you can convert by using molar mass. Since mass is in grams, we can use molar mass to convert moles to grams. This calls for the Ideal Gas Law.

Ideal Gas Law: PV=nRT

We manipulate the equation so that we are solving for moles, then convert moles to grams.

n=PV/RT

P= 100 kPa

V= 0.831 L

R= 8.31 kPa*L/mol*K

T= 27°C+273= 300 K

Now that we have our values listed, we can plug in to find moles.

n=\frac{(100kPa)(0.831L)}{(8.31kPa*l/molK)(300K)}

n=0.033mol

We use the molar mass of NO₂ to find grams.

0.033mol*\frac{46.005g}{1mol }=1.52 g

The mass is 1.52 g.

2. To calculate the temperature, we need to use the Ideal Gas Law.

Ideal Gas Law: PV=nRT

We can manipulate the equation so that we are solving for temperature.

T=PV/nR

P= 700.0 kPa

V= 33.2 L

R= 8.31 kPa*L/mol*K

n= 70 mol

Now that we have our values, we can plug in and solve for temperature.

T=\frac{(700kPa)(33.2L)}{(70mol)(8.31 kPa*L/molK)}

T=40K

The temperature is 40 K.

3 0
3 years ago
During a qualitative analysis, a student is looking for the presence of carbonate ions CO3(2-) in various solid samples. which o
Mama L [17]

The correct answer is (B) Adding a dilute solution of HCl

<u>EXPLANATION</u>

The presence of carbonate ions can be tested by adding a dilute acid to the solution. The acid displaces Carbon (IV) oxide from the solution. Using HCl, and a carbonate of metal X.

XCO₃₍s₎ + 2HCl₍aq₎⇒ XCl₂₍aq₎+ H₂O₍l₎ + CO₂₍g₎

The gas produced is tested using calcium hydroxide to confirm whether it is carbon (IV) oxide.

4 0
3 years ago
A chemist mixes 1.00 g CuCl2 with an excess of (NH4)2HPO4 in dilute aqueous solution . He measures the evolution of 670 J of hea
kaheart [24]

Answer:

\Delta H will be 90054 J

Explanation:

Number of moles = (mass)/(molar mass)

Molar mass of CuCl_{2} = 134.45 g/mol

So, 1.00 g of CuCl_{2} = \frac{1.00}{134.45}mol of CuCl_{2} = 0.00744 mol of CuCl_{2}

0.00744 mol of CuCl_{2} produces 670 J of heat

So, 1 mol of CuCl_{2} produces \frac{670}{0.00744}J of heat or 90054 J of heat

4 0
4 years ago
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