Consider the halogenation of ethene is as follows:
CH₂=CH₂(g) + X₂(g) → H₂CX-CH₂X(g)
We can expect that this reaction occurring by breaking of a C=C bond and forming of two C-X bonds.
When bond break it is endothermic and when bond is formed it is exothermic.
So we can calculate the overall enthalpy change as a sum of the required bonds in the products:
Part a)
C=C break = +611 kJ
2 C-F formed = (2 * - 552) = -1104 kJ
Δ H = + 611 - 1104 = - 493 kJ
2C-Cl formed = (2 * -339) = - 678 kJ
ΔH = + 611 - 678 = -67 kJ
2 C-Br formed = (2 * -280) = -560 kJ
ΔH = + 611 - 560 = + 51 kJ
2 C-I Formed = (2 * -209) = -418 kJ
ΔH = + 611 - 418 = + 193 kJ
Part b)
As we can see that the highest exothermic bond formed is C-F bond so from bond energies we can found that addition of fluoride is the most exothermic reaction
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Neo-pentane represents the Compound A while compound B is n-pentane.
After careful consideration we can say that compounds A and B are alkanes and also isomers of pentane. In chemistry, Isomers are defined as compounds having same empirical molecular formula but different structural formulas due to varying arrangement of atoms.
Now, as per the question statement, compound A gives a single monochlorination product upon heating with the molecule of chlorine i.e. Cl2 showing that the molecule is extremely symmetric. This molecule must be neo-pentane. Refer to image 1.
Similarly, Compound B forms 3 constitutional isomers after undergoing monochlorination. This compound must be n-pentane since three are 3 different types of carbon atoms in the structure. Refer to image 2.
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Answer:
Explanation:
Mg²⁺ is divalent , hence
Molecular weight / 2 = equivalent weight .
.25 moles = 2 x .25 equivalents = .5 equivalents .
Cl⁻ is monovalent so
molecular weight = equivalent weight
.50 mole = .50 equivalent
Total equivalent = .50 of Mg²⁺ + .50 of Cl⁻
= 1 equivalent .
A I think I could be wrong I’m not good at this